CODEWITHSUNDEEP
pythonimagenumpypython-imaging-library
Vicky Liau
Vicky Liau

Reputation: 617

read big image file as an array in python

Does anyone know how to open a large imagery file using python? I tried to open an imagery file (about 2 GB) through windows command prompt using ipython, but it crashes every time after I change image values into an array.

My laptop is window7-64bit with 4GB ram and Intel(R) Core(TM) i7-2860 QM CPU.

The error message is: python.exe has stopped working A problem caused the program to stop working correctly. Windows will close the program and notify you if a solution is available

Here is my code. 

import Image
import numpy as num
im=Image.open('myimage.tif')
imarray=num.array(im)

Upvotes: 3

Views: 11100

Answers (2)

Levon
Levon

Reputation: 143017

I don't know about using numpy with the PIL, but here's how I read the pixel data into an array (this uses a .jpg image). In the past this has worked well, but I don't think I've tried this with huge images, so your problem may boil down to memory issues.

import Image
im = Image.open('pic.jpg')

pix_ar = im.load()       # load image into 2D array
red_pixel = 255, 0, 0    # a red RGB pixel

and access individual elements like this:

x = 10
y = 5
print pix_ar[x, y]
(255, 255, 255)

or assign values

pix_ar[x, y] = red_pixel

Re memory: a 2GB image may end up taking much more RAM than 2 GB once it's "unpacked" into individual pixel values, it depends on how efficient the data structures are that store this information for you once you read it into some variable/data structure. 4 GB of RAM is unlikely to be sufficient considering that you are also running the OS and some other apps concurrently while also trying to read this big file into memory.

Also, if you have successfully transferred/read files opened with the PIL to numpy in the past, the above code may not be helpful.

Upvotes: 2

alexis
alexis

Reputation: 50180

How much RAM do you have? You'll need quite a bit more than 2GB of RAM to store a 2-gig image. I don't know how efficient Image is at storing images, but a list of bytes uses four bytes of space for each element in the list, so you'll burn more than 8GB of (virtual) memory... and a lot of patience. Edit: Since you only have 4 (or 3) GB to play with, this is almost certainly your problem.

But why are you trying to convert it to a numeric array? Use the methods of the im object returned by Image.open, as in the PIL Tutorial.

I don't know what you're doing with the image, but perhaps you can do it without reading the entire image in memory, or at least without converting the entire object into a numpy array. Read it bit by bit if possible to avoid blowing up your machine: Read up on python generators, and see the Image.getdata() method, which returns your image one pixel value at a time.

Upvotes: 7

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