Reputation: 14100
How do I convert the integer value "45" into the string value "45" in Excel VBA?
Upvotes: 188
Views: 1107507
Reputation: 7146
Try the CStr() function
Dim myVal as String
Dim myNum as Integer
myVal = "My number is:"
myVal = myVal & CStr(myNum)
Upvotes: 102
Reputation: 11
It might be worth adding a trim to your conversion too, as integers convert with a leading space for inferred (positive sign) and applied (negative sign) values.
For comparison:
1/
lsDogsAge = "Barker is " & Cstr(liAgeInteger) & "years old"
2/
lsDogsAge = "Barker is " & Trim(Cstr(liAgeInteger)) & "years old"
1/ Barker is__7
2/ Barker is_7
Ironically this forum's software automatically truncates double spaces, so I've use underscores
Upvotes: 0
Reputation: 159
Sub NumToText(ByRef sRng As String, Optional ByVal WS As Worksheet)
'---Converting visible range form Numbers to Text
Dim Temp As Double
Dim vRng As Range
Dim Cel As Object
If WS Is Nothing Then Set WS = ActiveSheet
Set vRng = WS.Range(sRng).SpecialCells(xlCellTypeVisible)
For Each Cel In vRng
If Not IsEmpty(Cel.Value) And IsNumeric(Cel.Value) Then
Temp = Cel.Value
Cel.ClearContents
Cel.NumberFormat = "@"
Cel.Value = CStr(Temp)
End If
Next Cel
End Sub
Sub Macro1()
Call NumToText("A2:A100", ActiveSheet)
End Sub
Reffer: MrExcel.com – Convert numbers to text with VBA
Upvotes: 2
Reputation: 592
The accepted answer is good for smaller numbers, most importantly while you are taking data from excel sheets. as the bigger numbers will automatically converted to scientific numbers i.e. e+10.
So I think this will give you more general answer. I didn't check if it have any downfall or not.
CStr(CDbl(#yourNumber#))
this will work for e+ converted numbers! as the just CStr(7.7685099559e+11)
will be shown as "7.7685099559e+11" not as expected: "776850995590" So I rather to say my answer will be more generic result.
Regards, M
Upvotes: 1
Reputation: 7083
Most times, you won't need to "convert"; VBA will do safe implicit type conversion for you, without the use of converters like CStr
.
The below code works without any issues, because the variable is of Type String, and implicit type conversion is done for you automatically!
Dim myVal As String
Dim myNum As Integer
myVal = "My number is: "
myVal = myVal & myNum
Result:
"My number is: 0"
You don't even have to get that fancy, this works too:
Dim myString as String
myString = 77
"77"
The only time you WILL need to convert is when the variable Type is ambiguous (e.g., Type Variant, or a Cell's Value
(which is Variant)).
Even then, you won't have to use CStr
function if you're compounding with another String variable or constant. Like this:
Sheet1.Range("A1").Value = "My favorite number is " & 7
"My favorite number is 7"
So, really, the only rare case is when you really want to store an integer value, into a variant or Cell value, when not also compounding with another string (which is a pretty rare side case, I might add):
Dim i as Integer
i = 7
Sheet1.Range("A1").Value = i
7
Dim i as Integer
i = 7
Sheet1.Range("A1").Value = CStr(i)
"7"
Upvotes: 57
Reputation: 22876
The shortest way without declaring the variable is with Type Hints :
s$ = 123 ' s = "123"
i% = "123" ' i = 123
This will not compile with Option Explicit
. The types will not be Variant
but String
and Integer
Upvotes: 3
Reputation: 152
If you have a valid integer value and your requirement is to compare values, you can simply go ahead with the comparison as seen below.
Sub t()
Dim i As Integer
Dim s As String
' pass
i = 65
s = "65"
If i = s Then
MsgBox i
End If
' fail - Type Mismatch
i = 65
s = "A"
If i = s Then
MsgBox i
End If
End Sub
Upvotes: 0
Reputation: 1
Another way to do it is to splice two parsed sections of the numerical value together:
Cells(RowNum, ColumnNum).Value = Mid(varNumber,1,1) & Mid(varNumber,2,Len(varNumber))
I have found better success with this than CStr()
because CStr()
doesn't seem to convert decimal numbers that came from variants in my experience.
Upvotes: 0
Reputation: 895
In my case, the function CString was not found. But adding an empty string to the value works, too.
Dim Test As Integer, Test2 As Variant
Test = 10
Test2 = Test & ""
//Test2 is now "10" not 10
Upvotes: 7
Reputation: 1282
If the string you're pulling in happens to be a hex number such as E01, then Excel will translate it as 0 even if you use the CStr function, and even if you first deposit it in a String variable type. One way around the issue is to append ' to the beginning of the value.
For example, when pulling values out of a Word table, and bringing them to Excel:
strWr = "'" & WorksheetFunction.Clean(.cell(iRow, iCol).Range.Text)
Upvotes: 3