Reputation: 3346
table offer
id_offer offer state
600 A 0
629 B 0
tags
id_tags tags
561 PHP
562 JAVA
589 MySQL
917 python
offer_has_tags
offer_id_offer tags_id_tags
600 561
600 562
600 917
629 562
629 589
629 917
The output that i need:
600 PHP
600 JAVA
600 python
629 JAVA
629 MySQL
629 python
What i am trying (without success):
SELECT A.id_offer, A.tags
FROM
( SELECT *
FROM offer
WHERE id_offer IN (600, 629)
AND state = 0
ORDER BY date_post DESC
LIMIT ?, ?
) A, tags A
INNER JOIN offer_has_tags B
ON A.id_tags = B.tags_id_tags
INNER JOIN offer C
ON C.id_offer = B.offer_id_offer
GROUP BY id_tags
Any idea? thanks
Upvotes: 1
Views: 53
Reputation: 1754
Using Old SQL style(but more understandable I think):
SELECT id_offer, tags.tags
FROM tags,offer_has_tags,offer
WHERE offer_id_offer = offer.id_offer
AND tags_id_tags = id_tags
AND id_offer IN (600, 629)
AND state = 0
GROUP BY id_offer, tags.tags
ORDER BY date_post DESC
with LIMIT:
SELECT A.id_offer, tags.tags
FROM tags,( SELECT *
FROM offer
WHERE id_offer IN (600, 629)
AND state = 0
ORDER BY date_post DESC
LIMIT ?, ?
) A,offer_has_tags
WHERE offer_id_offer = A.id_offer
AND tags_id_tags = id_tags
GROUP BY A.id_offer, tags.tags
Upvotes: 1
Reputation: 26396
try this
SELECT A.id_offer, t.tags
from
(Select * from offer o
Where o.id_offer IN (600, 629)
AND o.State=0
ORDER BY ? DESC
Limit ?,?) A
INNER JOIN offer_has_tags B
ON A.id_offer = B.offer_id_offer
INNER JOIN tags t
ON b.tags_id_tags = t.id_tags
Upvotes: 2