CODEWITHSUNDEEP
c#.netc#-4.0
Indish
Indish

Reputation: 749

C# : Split a sequence of numbers after given parameter length

I have a number something like this : 12345668788451223356456898941220036696897894

Now, the question is how can I split the number after each 8 digits.That is, I need the output as : 12345668

78845122 and so on up to the end of the number. If I convert it to string, I don't have a method so that I could split it only with length parameter.

Thanks in advance for answering.

Upvotes: 0

Views: 521

Answers (3)

Jon Skeet
Jon Skeet

Reputation: 1502386

String approach

If I convert it to string, I don't have a method so that I could split it only with length parameter.

Well you have Substring, don't you? You could use LINQ:

var numbers = Enumerable.Range(0, bigNumber.Length / 8)
                        .Select(x => bigNumber.Substring(x * 8, 8)
                        .ToList();

or a straight loop:

var numbers = new List<string>();
for (int i = 0; i < bigNumber.Length / 8; i++)
{
    numbers.Add(bigNumber.Substring(i * 8, 8);
}

If you need to end up with a List<int> instead, just add a call to int.Parse in there.

(You should check that the input string length is a multiple of 8 first.)

BigInteger approach

It's not clear what form you have this number in to start with. If it's a BigInteger, you could keep using DivRem:

BigInteger value = ...;
List<BigInteger> results = new List<BigInteger>();
BigInteger divisor = 100000000L;
for (int i = 0; i < count; i++)
{
    BigInteger tmp;
    value = BigInteger.DivRem(value, divisor, out tmp);
    results.Add(tmp);
}

Note that I'm using count here rather than just looping until value is 0, in case you have lots of leading 0s. You need to know how many numbers you're trying to extract :)

Upvotes: 4

Shant
Shant

Reputation: 237

Have you tried using 

string string.substring(int startIndex,int length)

In you case, you can write a loop to extract the 8 digits from the string till all the numbers are extracted

string sDigits = "12345668788451223356456898941220036696897894";
int iArrLen = sDigits.length / 8;
string[] sArrDigitList = new string[iArrLen];

for(int i=0; i < sDigits.length; i++)
{
   sArrDigitList[i] = sDigits.substring(0, 8);
   sDigits = sDigits.substring(sDigits.length-8);
}

Upvotes: 0

Siva Charan
Siva Charan

Reputation: 18064

Use this regex to split after each 8 digits,

\d{1,8}

OR

(\d{1,8})

Output:

12345668
78845122
33564568
98941220
03669689
7894

Upvotes: 2

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