CODEWITHSUNDEEP
phpjavascriptjqueryjson
Valerie Parker
Valerie Parker

Reputation: 29

JSON returned from php is [obejct Object] and jQuery.parseJSON is null

In my php file I have:

$arr[] = array("status"=>0);
echo json_encode($arr);

In my javascript, I have:

$(document).ready(function(){

    initialize(); 
    $("#searchbutton").click(function(){

    var usrinput = $("#userinput").val();

    $.get(
        "searchpageajaxjson.php",
        {searchterm: usrinput},
        function(data){
            searchreturned(data);
        },
        "json"
    ); 
    });
 });


function searchreturned(data){
   console.log(data); 
   var parsed = jQuery.parseJSON(data);
   console.log(parsed); 
   //for (var i = 0; i < parsed.length; i++) {  
    //            alert(parsed[i]);  
    //     } 
   //    
}

The console.log(data) shows [object Obejct] and console.log(parsed) shows null

Where am I going wrong?

Edited to Add:

alert(data.status) shows undefined.

Second Edit:

I'm really grateful for all the help I've received. It's hard to pick an answer, because I'm really only able to move on from this problem due to all the help received in all the comments. I am always in awe of you kind folks who give your time to helping newbies like myself.

Upvotes: 2

Views: 1213

Answers (2)

Oscar Jara
Oscar Jara

Reputation: 14187

1. There is no reason to call jQuery.parseJSON or $.parseJSON because jQuery knows that is already a JSON object due to the "json" parameter you passed here:

$.get('source', {param:param}, function(data){ /*work with data*/ }, "json");

2. If console.log(data); is not null and you are getting some [Object Object] try to see what are the properties of that object, like this:

e.g: Explore your object:

enter image description here

e.g: Print value from object:

//this will output "Horror"
data.genre

Hope this helps you.

Upvotes: 1

Ry-
Ry-

Reputation: 225124

You're not supposed to call jQuery.parseJSON on data again. jQuery takes care of that for you already, since you used "json" as the dataType.

Upvotes: 2

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