user541686
user541686

Reputation: 210455

Which operations must not throw an exception in C++?

Today I learned that swap is not allowed to throw an exception in C++.

I also know that the following cannot throw exceptions either:

Are there any others?
Or perhaps, is there some sort of list that mentions everything that may not throw?
(Something more succinct than the standard itself, obviously.)

Upvotes: 23

Views: 2862

Answers (3)

Jon Kalb
Jon Kalb

Reputation: 103

If you want the in-exhaustive-detail answer to this question go to http://exceptionsafecode.com/ and either watch the 85 min video that covers just C++03 or the three hour (in two parts) video that covers both C++03 and C++11.

When writing Exception-Safe code, we assume all functions throw, unless we know different.

In short,

*) Fundamental types (including arrays of and pointers to) can be assigned to and from and used with operations that don't involve user defined operators (math using only fundamental integers and floating point values for example). Note that division by zero (or any expression whose result is not mathematically defined) is undefined behavior and may or may not throw depending on the implementation.

*) Destructors: There is nothing conceptually wrong with destructors that emit exceptions, nor does the standard prohibited them. However, good coding guidelines usually prohibit them because the language doesn't support this scenario very well. (For example, if destructors of objects in STL containers throw, the behavior is undefined.)

*) Using swap() is an important technique for providing the strong exception guarantee, but only if swap() is non-throwing. In general, we can't assume that swap() is non-throwing, but the video covers how to create a non-throwing swap for your User-Defined Types in both C++03 and C++11.

*) C++11 introduces move semantics and move operations. In C++11, swap() is implemented using move semantics and the situation with move operations is similar to the situation with swap(). We cannot assume that move operations do not throw, but we can generally create non-throwing move operations for the User-Defined Types that we create (and they are provided for standard library types). If we provide non-throwing move operations in C++11, we get non-throwing swap() for free, but we may choose to implement our own swap() any way for performance purposes. Again, this is cover in detail in the video.

*) C++11 introduces the noexcept operator and function decorator. (The "throw ()" specification from Classic C++ is now deprecated.) It also provides for function introspection so that code can be written to handle situations differently depending on whether or not non-throwing operations exist.

In addition to the videos, the exceptionsafecode.com website has a bibliography of books and articles about exceptions which needs to be updated for C++11.

Upvotes: 6

Pyrce
Pyrce

Reputation: 8571

So this doesn't perfectly answer you question -- I searched for a bit out of my own curiosity -- but I believe that nothrow guaranteed functions/operators mostly originate from any C-style functions available in C++ as well as a few functions which are arbitrarily simple enough to give such a guarantee. In general it's not expected for C++ programs to provide this guarantee ( When should std::nothrow be used? ) and it's not even clear if such a guarantee buys you anything useful in code that makes regular use of exceptions. I could not find a comprehensive list of ALL C++ functions that are nothrow functions (please correct me if I missed a standard dictating this) other than listings of swap, destructors, and primitive manipulations. Also it seems fairly rare for a function that isn't fully defined in a library to require the user to implement a nothrows function.

So perhaps to get to the root of your question, you should mostly assume that anything can throw in C++ and take it as a simplification when you find something that absolutely cannot throw an exception. Writing exception safe code is much like writing bug free code -- it's harder than it sounds and honestly is oftentimes not worth the effort. Additionally there are many levels between exception unsafe code and strong nothrow functions. See this awesome answer about writing exception safe code as verification for these points: Do you (really) write exception safe code?. There's more information about exception safety at the boost site http://www.boost.org/community/exception_safety.html.

For code development, I've heard mixed opinions from Professors and coding experts on what should and shouldn't throw an exception and what guarantees such code should provide. But a fairly consistent assertion is that code which can easily throw an exception should be very clearly documented as such or indicate the thrown capability in the function definition (not always applicable to C++ alone). Functions that can possible throw an exception are much more common than functions that Never throw and knowing what exceptions can occur is very important. But guaranteeing that a function which divides one input by another will never throws a divide-by-0 exception can be quite unnecessary/unwanted. Thus nothrow can be reassuring, but not necessary or always useful for safe code execution.

In response to comments on the original question:

People will sometimes state that exception throwing constructors are evil when throw in containers or in general and that two-step initialization and is_valid checks should always be used. However, if a constructor fails it's oftentimes unfixable or in a uniquely bad state, otherwise the constructor would have resolved the problem in the first place. Checking if the object is valid is as difficult as putting a try catch block around initialization code for objects you know have a decent chance of throwing an exception. So which is correct? Usually whichever was used in the rest of the code base, or your personal preference. I prefer exception based code as it gives me a feeling of more flexibility without a ton of baggage code of checking every object for validity (others might disagree).

Where does this leave you original question and the extensions listed in the comments? Well, from the sources provided and my own experience worrying about nothrow functions in an "Exception Safety" perspective of C++ is oftentimes the wrong approach to handling code development. Instead keep in mind the functions you know might reasonably throw an exception and handle those cases appropriately. This is usually involving IO operations where you don't have full control over what would trigger the exception. If you get an exception that you never expected or didn't think possible, then you have a bug in your logic (or your assumptions about the function uses) and you'll need to fix the source code to adapt. Trying to make guarantees about code that is non-trivial (and sometimes even then) is like saying a sever will never crash -- it might be very stable, but you'll probably not be 100% sure.

Upvotes: 9

There is a great difference between cannot and should not. Operations on primitive types cannot throw, as many functions and member functions, including many operations in the standard library and/or many other libraries.

Now on the should not, you can include destructors and swap. Depending on how you implement them, they can actually throw, but you should avoid having destructors that throw, and in the case of swap, providing a swap operation with the no-throw guarantee is the simplest way of achieving the strong exception guarantee in your class, as you can copy aside, perform the operation on the copy, and then swap with the original.

But note that the language allows both destructors and swap to throw. swap can throw, in the simplest case if you do not overload it, then std::swap performs a copy construction, an assignment and a destruction, three operations that can each throw an exception (depending on your types).

The rules for destructors have changed in C++11, which means that a destructor without exception specification has an implicit noexcept specification which in turn means that if it threw an exception the runtime will call terminate, but you can change the exception specification to noexcept(false) and then the destructor can also throw.

At the end of the day, you cannot provide exception guarantees without understanding your code base, because pretty much every function in C++ is allowed to throw.

Upvotes: 17

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