CODEWITHSUNDEEP
javaspringspring-el
user1293071
user1293071

Reputation: 263

Handle null values in spring expression language

I have the following code using spring expression language:

StandardEvaluationContext stdContext = new StandardEvaluationContext();
stdContext.setVariable("emp", filterInputData); 
ExpressionParser parser = new SpelExpressionParser();     
parser.parseExpression("#emp.?[name.toLowerCase().contains('Hari')]").getValue(stdContext);

where emp is the name of the bean. Here the name can be null and when calling name.toLowerCase() I am getting a nullpointer exception. How to handle the null values in this scenario? I need to call toLowercase() for only non-null values.

Upvotes: 16

Views: 42995

Answers (2)

Gary Russell
Gary Russell

Reputation: 174829

"#emp.name != null ? #emp.name.toLowerCase().contains('hari') : null"

or

"#emp.name != null ? #emp.name.toLowerCase().contains('hari') : false"

depending on what you want back when the name is missing.

Actually, this short form works too...

"#emp.name != null ? toLowerCase().contains('hari') : null"

BTW, in your original question...

name.toLowerCase().contains('Hari')

will never return true (H is upper case).

Or, Elvis is your friend...

Expression expression = new SpelExpressionParser().parseExpression("#emp.name?:'no name found'");
value = expression.getValue(context, String.class).toLowerCase();

Upvotes: 37

Tomer
Tomer

Reputation: 2448

Can you Autowire this bean to your class?

Something like:

public class YourClass{ 
    @Autowire
    private Employee emp

    public boolean func(){
        if (emp.getName() != null){
            return emp.getName().toLowerCase().contains('Hari');
        }else{
            return false;
        }
    }
}

Upvotes: -1

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