CODEWITHSUNDEEP
c#
Bill Software Engineer
Bill Software Engineer

Reputation: 7782

How to invoke a function with type?

So I have this custom object / static function that take a Type to call:

      MyObject<MyType>.MyFunction();

MyObject is defined as such:

      public abstract class MyObject <type> { ... }

How do I invoke it? The reason I need to do invoking is because MyType is dynamic, and I can't do this:

     Type t = this.GetType();
     MyObject<t>.MyFunction();

Upvotes: 2

Views: 134

Answers (4)

Sergei Rogovtcev
Sergei Rogovtcev

Reputation: 5832

Only by using reflection.

typeof(MyObject<>).MakeGenericType(t).GetMethod("MyFunction", BindingFlags.Static).Invoke(null, new object[0]);

Upvotes: 1

Codeman
Codeman

Reputation: 12375

Are you aware of the keyword typeof ?

This should work just fine: msdn.microsoft.com/en-us/library/twcad0zb(v=vs.80).aspx

Upvotes: 0

MikeP
MikeP

Reputation: 7959

typeof(MyObject<>).MakeGenericType(this.GetType())
    .GetMethod("MyFunction", BindingFlags.Static | BindingFlags.Public)
    .Invoke(null, null);

Upvotes: 1

Jon Skeet
Jon Skeet

Reputation: 1500675

You'd need to use reflection to instantiate the class - and then more reflection to invoke the method:

Type typeDefinition = typeof(MyObject<>);
Type constructedType = typeDefinition.MakeGenericType(t);
MethodInfo method = constructedType.GetMethod("MyFunction");
method.Invoke(null, null);

It's unpleasant, certainly. Do you definitely need it to be a method in a generic class?

Upvotes: 4

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