CODEWITHSUNDEEP
python
ehertele
ehertele

Reputation: 221

datetime objects format

I am trying to use datetime objects, including datetime.month, datetime.day, and datetime.hour.

The problem is that these objects (say datetime.month) give values as 1, 2, 3, and so on to 12. Instead, I need these in the format 01,02,03 and so on to 12. There's a similar issue with days and months.

How can I switch to this format?

I realized this wasn't a very clear question:

I'm using string formatting to print values from a dictionary I have with timestamps.

So, the expression is roughly:

print "%s-%s-%s"%(date.year, date.month, date.day, etc., len(str) )

My values were originally in the correct "%Y-%m-%d form (such as 2000-01-01). Using the above, I get 2000-1-1.

Upvotes: 14

Views: 21500

Answers (4)

Aldo Lammel
Aldo Lammel

Reputation: 31

Wiki: https://www.w3schools.com/python/python_datetime.asp

You can check the strftime() method. Look this out:

from datetime import datetime

today = datetime.today()

print(today.strftime("%Y%m%d"))  # yyyyMMdd

Upvotes: 0

Danil
Danil

Reputation: 5181

zfill is easier to remember:

In [19]: str(dt.month).zfill(2)
Out[19]: '07'

Upvotes: 2

mgilson
mgilson

Reputation: 309889

You can print the individual attributes using string formatting:

print ('%02d' % (mydate.month))

Or more recent string formatting (introduced in python 2.6):

print ('{0:02d}'.format(a.month))  # python 2.7+ -- '{:02d}' will work

Note that even:

print ('{0:%m}'.format(a))  # python 2.7+ -- '{:%m}' will work.

will work.

or alternatively using the strftime method of datetime objects:

print (mydate.strftime('%m'))

And just for the sake of completeness:

print (mydate.strftime('%Y-%m-%d'))

will nicely replace the code in your edit.

Upvotes: 32

Ricardo Altamirano
Ricardo Altamirano

Reputation: 15198

You can convert them to strings and simply pad them:

import datetime

d = datetime.datetime(2012, 5, 25)

m = str(d.month).rjust(2, '0')
print(m) # Outputs "05"

Or you could just a str.format:

import datetime

d = datetime.datetime(2012, 5, 25)

print("{:0>2}".format(d.month))

EDIT: To answer the updated question, have you tried this?

import datetime
d = datetime.datetime(2012, 5, 25)
print("{:0>4}-{:0>2}-{:0>2}".format(d.year, d.month, d.day))

You said you were originally printing them using string formatting, so what did you change? This code:

print "%s-%s-%s"%(date.year, date.month, date.day, etc., len(str) )

Doesn't really make any sense, since I'm a little unclear as to what arguments you are passing in. I assume just date.year, date.month, and date.day, but it's unclear. What action are you performing with len(str)?

Upvotes: 1

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