CODEWITHSUNDEEP
python
Kostas Di
Kostas Di

Reputation: 111

Remove utm_* parameters from URL in Python

I've been trying to remove all utm_* parameters from a list of URLs. The closest thing I have found is this: https://gist.github.com/626834.

Any ideas?

Upvotes: 8

Views: 4334

Answers (6)

dw1
dw1

Reputation: 1845

The popular url modules answer modifies and rearranges the parameters which can break poorly-designed sites (see the comment) so I settled on regex, but there are problems with those I tried, too. My final result is this:

import re

def removeURLTracking(url):
    url = re.sub(r'(?<=[?&])utm_[^&#]+&?', '', url)
    url = url.replace('&#', '#').rstrip('?&')
    return url

tests = ["http://localhost/index.php?a=1&utm_source=1&b=2",
         "http://localhost/index.php?a=1&utm_source=1&b=2#hash",
         "http://localhost/index.php?a=1&utm_source=1&b=2&utm_something=no#hash",
         "http://localhost/index.php?a=1&utm_source=1&utm_a=yes&b=2#hash",
         "http://localhost/index.php?utm_a=a",
         "http://localhost/index.php?a=utm_a",
         "http://localhost/index.php?a=1&b=2",
         "http://localhost/index.php",
         "http://localhost/index.php#hash2"
         ]

for t in tests:
    print(removeURLTracking(t))

"""
http://localhost/index.php?a=1&b=2
http://localhost/index.php?a=1&b=2#hash
http://localhost/index.php?a=1&b=2#hash
http://localhost/index.php?a=1&b=2#hash
http://localhost/index.php
http://localhost/index.php?a=utm_a
http://localhost/index.php?a=1&b=2
http://localhost/index.php
http://localhost/index.php#hash2
"""

Upvotes: 0

PHPGuyZim
PHPGuyZim

Reputation: 143

Using regex

import re
def clean_url(url):
    return re.sub(r'(?<=[?&])utm_[^&]+&?', '', url)

What's going on? We are using regular expressions to find all instances of strings that look like utm_somekey=somevalue which is preceded by either "?" or "&".

Testing it:

tests = [   "http://localhost/index.php?a=1&utm_source=1&b=2",
            "http://localhost/index.php?a=1&utm_source=1&b=2#hash",
            "http://localhost/index.php?a=1&utm_source=1&b=2&utm_something=no#hash",
            "http://localhost/index.php?a=1&utm_source=1&utm_a=yes&b=2#hash",
            "http://localhost/index.php?utm_a=a",
            "http://localhost/index.php?a=utm_a",
            "http://localhost/index.php?a=1&b=2",
            "http://localhost/index.php",
            "http://localhost/index.php#hash2"
        ]

for t in tests:
    print(clean_url(t))

http://localhost/index.php?a=1&b=2
http://localhost/index.php?a=1&b=2#hash
http://localhost/index.php?a=1&b=2&
http://localhost/index.php?a=1&b=2#hash
http://localhost/index.php?
http://localhost/index.php?a=utm_a
http://localhost/index.php?a=1&b=2
http://localhost/index.php
http://localhost/index.php#hash2

Upvotes: 0

Adders
Adders

Reputation: 665

How about this. Nice and simple:

url = 'https://searchengineland.com/amazon-q3-ad-revenues-surpass-1-billion-roughly-2x-early-2016-285763?utm_source=feedburner&utm_medium=feed&utm_campaign=feed-main'

print url[:url.find('?utm')]

https://searchengineland.com/amazon-q3-ad-revenues-surpass-1-billion-roughly-2x-early-2016-285763

Upvotes: 1

jadkik94
jadkik94

Reputation: 7068

Simple, and works, and based on the link you posted, BUT it's re... so, not sure it won't break for some reason that I can't think of :)

import re

def trim_utm(url):
    if "utm_" not in url:
        return url
    matches = re.findall('(.+\?)([^#]*)(.*)', url)
    if len(matches) == 0:
        return url
    match = matches[0]
    query = match[1]
    sanitized_query = '&'.join([p for p in query.split('&') if not p.startswith('utm_')])
    return match[0]+sanitized_query+match[2]

if __name__ == "__main__":
    tests = [   "http://localhost/index.php?a=1&utm_source=1&b=2",
                "http://localhost/index.php?a=1&utm_source=1&b=2#hash",
                "http://localhost/index.php?a=1&utm_source=1&b=2&utm_something=no#hash",
                "http://localhost/index.php?a=1&utm_source=1&utm_a=yes&b=2#hash",
                "http://localhost/index.php?utm_a=a",
                "http://localhost/index.php?a=utm_a",
                "http://localhost/index.php?a=1&b=2",
                "http://localhost/index.php",
                "http://localhost/index.php#hash2"
            ]

    for t in tests:
        trimmed = trim_utm(t)
        print t
        print trimmed
        print

Upvotes: 1

Jon Clements
Jon Clements

Reputation: 142106

It's a bit long but uses the url* modules, and avoids re's.

from urllib import urlencode
from urlparse import urlparse, parse_qs, urlunparse

url = 'http://whatever.com/somepage?utm_one=3&something=4&utm_two=5&utm_blank&something_else'

parsed = urlparse(url)
qd = parse_qs(parsed.query, keep_blank_values=True)
filtered = dict( (k, v) for k, v in qd.iteritems() if not k.startswith('utm_'))
newurl = urlunparse([
    parsed.scheme,
    parsed.netloc,
    parsed.path,
    parsed.params,
    urlencode(filtered, doseq=True), # query string
    parsed.fragment
])

print newurl
# 'http://whatever.com/somepage?something=4&something_else'

Upvotes: 10

mVChr
mVChr

Reputation: 50177

import re
from urlparse import urlparse, urlunparse

url = 'http://www.someurl.com/page.html?foo=bar&utm_medium=qux&baz=qoo'
parsed_url = list(urlparse(url))
parsed_url[4] = '&'.join(
    [x for x in parsed_url[4].split('&') if not re.match(r'utm_', x)])
utmless_url = urlunparse(parsed_url)

print utmless_url  # 'http://www.someurl.com/page.html?foo=bar&baz=qoo'

Upvotes: 2

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