Reputation: 27875
I have a text file which have normal sentences. Actually I was in hurry while typing that file so I just capitalized the first letter of first word of the sentence (as per English grammar).
But now I want that it would be better if each word's first letter is capitalized. Something like:
Each Word of This Sentence is Capitalized
Point to be noted in above sentence is of and is are not capitalized, actually I want to escape the words which has equal to or less than 3 letters.
What should I do?
Upvotes: 4
Views: 3898
Reputation: 4552
You should split the words, and capitalise only those which are longer than three letters.
words.txt
:
each word of this sentence is capitalized
some more words
an other line
-
import string
with open('words.txt') as file:
# List to store the capitalised lines.
lines = []
for line in file:
# Split words by spaces.
words = line.split(' ')
for i, word in enumerate(words):
if len(word.strip(string.punctuation + string.whitespace)) > 3:
# Capitalise and replace words longer than 3 (without punctuation).
words[i] = word.capitalize()
# Join the capitalised words with spaces.
lines.append(' '.join(words))
# Join the capitalised lines.
capitalised = ''.join(lines)
# Optionally, write the capitalised words back to the file.
with open('words.txt', 'w') as file:
file.write(capitalised)
Upvotes: 3
Reputation: 45542
for line in text_file:
print ' '.join(word.title() if len(word) > 3 else word for word in line.split())
Edit: To omit counting punctuation replace len
with the following function:
def letterlen(s):
return sum(c.isalpha() for c in s)
Upvotes: 5
Reputation: 113975
What you really want is something called a list of stop words. In the absence of this list, you can build one yourself and do this:
skipWords = set("of is".split())
punctuation = '.,<>{}][()\'"/\\?!@#$%^&*' # and any other punctuation that you want to strip out
answer = ""
with open('filepath') as f:
for line in f:
for word in line.split():
for p in punctuation:
# you end up losing the punctuation in the outpt. But this is easy to fix if you really care about it
word = word.replace(p, '')
if word not in skipwords:
answer += word.title() + " "
else:
answer += word + " "
return answer # or you can write it to file continuously
Upvotes: 1
Reputation: 20909
Take a look at NLTK.
Tokenize each word, and capitalize it. Words such as 'if', 'of' are called 'stop words'. If your criteria is solely the length, Steven's answer is a good way of doing so. In case you want to look up stop words, there is a similar question in SO: How to remove stop words using nltk or python.
Upvotes: 4
Reputation: 345
You could add all the elements from the text file to a list:
list = []
f.open('textdocument'.txt)
for elm in f (or text document, I\'m too tired):
list.append(elm)
And once you have all the elements in a list, run a for loop that checks each element's length, and if it's greater than three returns the first element upper-cased
new_list = []
for items in list:
if len(item) > 3:
item.title() (might wanna check if this works in this case)
new_list.append(item)
else:
new_list.append(item) #doesn't change words smaller than three words, just adds them to the new list
And see if that works?
Upvotes: 0