CODEWITHSUNDEEP
c++binaryhexiostreamcout
sfxworks
sfxworks

Reputation: 5

Reading/Displaying the actual byte (C++)

int main()
{
    cout << hex;
    cout << (0xe & 0x3); // 1110 & 0011 -> 0010 (AND)
    cout << endl;
    cout << (0xe | 0x3); // 1110 | 0011 -> 1111 (OR)
    cout << endl;
    cout << (0xe ^ 0x3); // 1110 ^ 0011 -> 1101 (XOR)
    return 0;
}

When using cout, it displays the translation (2, f, and d) vs the actual value (0010, 1111, and 1101). How do I make it so that it display this vs what the bit goes with?

Upvotes: 1

Views: 219

Answers (2)

Danil Speransky
Danil Speransky

Reputation: 30453

For example:

#include <iostream>
#include <string>

using namespace std;

string convBase(unsigned long v, long base) {
  if (base < 2 || base > 16) return "Error: base out of range;";

  string result;
  string digits = "0123456789abcdef";

  do {
    result = digits[v % base] + result;
    v /= base;
  } while (v);

  return result;
}

int main(int argc, char** argv) {
  int a = 0xe;
  int b = 0x3;

  cout << hex;

  cout << (a & b) << " - " << convBase(a & b, 2);
  cout << endl;
  cout << (a | b) << " - " << convBase(a | b, 2);
  cout << endl;
  cout << (a ^ b) << " - " << convBase(a ^ b, 2);
  cout << endl;

  return 0;
}

Output:

2 - 10 f - 1111 d - 1101

Upvotes: 1

Sergey Kalinichenko
Sergey Kalinichenko

Reputation: 726599

These are the correct values for the hex representation of the binary values that you have requested: 0010 is 2, 1111 is f, and 1101 is d.

If you would like to print a binary representation, you can borrow convBase function from here, or build your own.

cout << convBase((0xe & 0x3), 2); // 1110 & 0011 -> 0010 (AND)
cout << endl;
cout << convBase((0xe | 0x3), 2); // 1110 | 0011 -> 1111 (OR)
cout << endl;
cout << convBase((0xe ^ 0x3), 2); // 1110 ^ 0011 -> 1101 (XOR)

Upvotes: 3

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