Reputation: 908
How to arrange this array by last inner index ( 0, 1, 2 ) and get the value of the last inner index as the value of each second index:
Array
(
[text] => Array
(
[grid] => Array
(
[0] => 3
[1] => 4
[2] => 5
)
[image] => Array
(
[0] =>
[1] =>
[2] =>
)
[align] => Array
(
[0] => left
[1] => right
[2] => left
)
[title] => Array
(
[0] =>
[1] =>
[2] =>
)
[content] => Array
(
[0] =>
[1] =>
[2] =>
)
)
)
And have the results as below:
Array
(
[text] => Array
(
[0] => Array
(
[grid] => 3
[image] =>
[align] => left
[title] =>
[content] =>
)
[1] => Array
(
[grid] => 4
[image] =>
[align] => right
[title] =>
[content] =>
)
[2] => Array
(
[grid] => 5
[image] =>
[align] => left
[title] =>
[content] =>
)
)
)
Upvotes: 0
Views: 197
Reputation: 19445
As SiGanteng suggested, i dont see other ways than a for/foreach
loop:
function buildArray($source, $key = false)
{
// Build the new array
$new_array = array();
// Define groups
$groups = $key === false ? array_keys($source) : array($key);
foreach($groups AS $group)
{
// Get the keys
$keys = array_keys($array[$group]);
// Count the values
$num_entries = count($array[$group][$keys[0]]);
for($i = 0; $i < $num_entries; $i++)
{
foreach($keys AS $key)
{
$new_array[$group][$i][$key] = $array[$group][$key][$i];
}
}
}
return $new_array;
}
This allow you to define the key you need to build; If not specified, the function build the array for every key.
Upvotes: 1
Reputation: 964
This should work.
function formatit($arr) {
$new = array();
foreach($arr as $k=>$v) {
foreach($v as $k1=>$v1) {
$new[$k1][$k] = $v1;
}
}
return $new;
}
Tested. Call it as
$arr['text'] = formatit($arr['text']);
Upvotes: 0
Reputation: 1300
This will do the work
function restructure($arr){
$newArr = array();
foreach($arr as $k => $v){
foreach($v as $k1 => $v1){
foreach($v1 as $k2 => $v2){
$newArr[$k][$k2][$k1] = $v2;
}
}
}
return $newArr;
}
Upvotes: 2