CODEWITHSUNDEEP
php
Omar S.Ali
Omar S.Ali

Reputation: 45

Check an part of url exist in php

I have an URL:

http://abv.com/

How can I check if /en/ is in the URL, for example: 

 http://abv.com/en/

Upvotes: 1

Views: 462

Answers (4)

Lix
Lix

Reputation: 48006

You can take the URL and split it by slashes - use the .explode() function.

$url =  'http://abv.com/en/';
$urlParts = explode('/',$url);
array_shift($urlParts);
array_shift($urlParts);

Using array_shift() twice you remove the unwanted http and the blank item due to the double slash...

Array
(
    [0] => abv.com
    [1] => en
    [2] =>
)

.parse_url() also has some usefull features for dealing with URL strings. You should check it out also.

$url =  'http://abv.com/en/';
$urlParts = parse_url($url);
$pathParts = explode('/',$urlParts['path']);

Upvotes: 1

Ajay Patel
Ajay Patel

Reputation: 5418

You can seperate url using php explode function, then check if url having "en" (country code ) or not.

$url = 'http://abv.com/en/';
          $expurl = explode('/', $url);
          print_r($expurl);            
          foreach ($expurl as $key => $value) {
            if ($value == 'en') {
              # do what you want
            }
          }

Array result 

  Array ( [0] => http: [1] => [2] => abv.com [3] => en [4] => )

Upvotes: 1

Bram Verstraten
Bram Verstraten

Reputation: 1557

You can use strpos().

$mystring = 'abc';
$findme   = 'a';
$pos = strpos($mystring, $findme);

// The !== operator can also be used.  Using != would not work as expected
// because the position of 'a' is 0. The statement (0 != false) evaluates 
// to false.
if ($pos !== false) {
     echo "The string '$findme' was found in the string '$mystring'";
         echo " and exists at position $pos";
} else {
     echo "The string '$findme' was not found in the string '$mystring'";
}

Upvotes: 2

Diego Agulló
Diego Agulló

Reputation: 9586

The simplest way to do that is using strpos():

if (strpos($url, '/en/') !== false) {
    // found!
}

If you want to check just the path, though, using parse_url() can be helpful:

if (strpos(parse_url($url, PHP_URL_PATH), '/en/') !== false) {
    // found in the path!
}

Upvotes: 1

Related Questions