CODEWITHSUNDEEP
c#regex
Rocky Singh
Rocky Singh

Reputation: 15430

Find a pattern in string and replace it

I need to parse the following format @[Alphanumeric1](Alphanumeric2:Alphanumeric3) from a long string. Below is my string:

This is a long text 
@[Alphanumeric1](Alphanumeric2:Alphanumeric3) again long text 
@[Alphanumeric11](Alphanumeric22:Alphanumeric33) again long text
@[Alphanumeric111](Alphanumeric222:Alphanumeric333)

I need all the occurence of(@[Alphanumeric1](Alphanumeric2:Alphanumeric3)) to be replaced by value which is coming after colon(:) i.e I want the output as 

This is a long text 
Alphanumeric3 again long text 
Alphanumeric33 again long text
Alphanumeric333

Upvotes: 1

Views: 474

Answers (3)

Alexander Malfait
Alexander Malfait

Reputation: 2701

This should do the trick:

class Program
{
    static void Main(string[] args)
    {
        string data = @"This is a long text 
@[Alphanumeric1](Alphanumeric2:Alphanumeric3) again long text 
@[Alphanumeric11](Alphanumeric22:Alphanumeric33) again long text
@[Alphanumeric111](Alphanumeric222:Alphanumeric333)";

        Debug.WriteLine(ReplaceData(data));
    }

    private static string ReplaceData(string data)
    {
        return Regex.Replace(data, @"@\[.+?\]\(.*?:(.*?)\)", match => match.Groups[1].ToString());
    }
}

Upvotes: 0

newfurniturey
newfurniturey

Reputation: 38436

The following regex should by able to handle that input:

(@\[[a-zA-Z0-9]+\]\([a-zA-Z0-9]+:(?<match>[a-zA-Z0-9]+)\))

Used in C#, the following will find & replace all instances in a string input:

string output = Regex.Replace(input, @"(@\[[a-zA-Z0-9]+\]\([a-zA-Z0-9]+:(?<match>[a-zA-Z0-9]+)\))", "${match}");

Regex Explained:

(                           # beginning of group to find+replace
    @                       # match the '@'
    \[                      # match the '['
        [a-zA-Z0-9]+        # alpha-numeric match
    \]                      # match the ']'
    \(                      # match the '('
        [a-zA-Z0-9]+        # alpha-numeric match
        :                   # match the ':'
        (?<match>           # beginning of group to use for replacement
            [a-zA-Z0-9]+    # alpha-numeric match
        )
    \)                      # match the ')'
)

Upvotes: 0

David B
David B

Reputation: 2698

@\[[\w\d]*\]\([\w\d]*:([\w\d]*)\)

That will match the three strings above, and grab the alphanumeric string after the : in group 1. Play with the regex here.

Upvotes: 2

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