Reputation: 17530
Q> If showing all the RGB pixel value of a 60*66 PNG image takes 10-34 seconds then how Image Viewer shows image instantly ?
Dim clr As Integer ' or string
Dim xmax As Integer
Dim ymax As Integer
Dim x As Integer
Dim y As Integer
Dim bm As New Bitmap(dlgOpen.FileName)
xmax = bm.Width - 1
ymax = bm.Height - 1
For y = 0 To ymax
For x = 0 To xmax
With bm.GetPixel(x, y)
clr = .R & .G & .B
txtValue.AppendText(clr)
End With
Next x
Next y
Dim bmp As New Bitmap(dlgOpen.FileName)
Dim rect As New Rectangle(0, 0, bmp.Width, bmp.Height)
Dim bmpData As System.Drawing.Imaging.BitmapData = bmp.LockBits(rect,Drawing.Imaging.ImageLockMode.ReadWrite, bmp.PixelFormat)
Dim ptr As IntPtr = bmpData.Scan0
Dim bytes As Integer = Math.Abs(bmpData.Stride) * bmp.Height
Dim rgbValues(bytes - 1) As Byte
System.Runtime.InteropServices.Marshal.Copy(ptr, rgbValues, 0, bytes)
For counter As Integer = 0 To rgbValues.Length - 1
txtValue.AppendText(rgbValues(counter))
Next
System.Runtime.InteropServices.Marshal.Copy(rgbValues, 0, ptr, bytes)
bmp.UnlockBits(bmpData)
The first code takes 10 seconds and the 2nd one around 34 seconds for showing all the value in a textbox for a 59*66 PNG image on AMD A6 3500 with 4 GB RAM !
Upvotes: 1
Views: 10794
Reputation: 2114
The problem is that the feature you're using, GetPixel, is very slow if you need to access a lot of pixels. Try using LockBits. You can use that to gather image data nearly instantly.
Using the LockBits method to access image data.
Upvotes: 1