RCIX
RCIX

Reputation: 39437

.NET Framework Library for arbitrary digit precision

I'm reviving this question, and making it more specific: Is there a .NET framework library that supports numbers with arbitrary digits of precision?

Upvotes: 2

Views: 3995

Answers (8)

Emil
Emil

Reputation: 21

If you want a really fast library then try:

http://www.emilstefanov.net/Projects/GnuMpDotNet/

Upvotes: 2

jasonh
jasonh

Reputation: 30303

Can you wait for .NET 4.0? They're bringing BigInteger directly into the Framework.

On the other hand, if you can't wait, then the J# runtime includes built-in support for java.math.BigInteger and BigDecimal. This is redistributable just like the rest of the .NET Framework.

Upvotes: 6

Reed Copsey
Reed Copsey

Reputation: 564413

There are a few options here.

A good option is W3b.Sine, which is native C#/.NET, and supports arbitrary precision floating point values.

If you are only dealing with integer values, IntX provides support for arbitrary precision integer values. A potentially more mature option would be C# BigInt, but again, this will not support floating point operations.

Upvotes: 5

Vladislav Rastrusny
Vladislav Rastrusny

Reputation: 29985

GnuMpDotNet: http://www.emilstefanov.net/Projects/GnuMpDotNet/

If you need pure .NET consider looking into this: http://www.codeplex.com/IntX/

Upvotes: 3

Doug McClean
Doug McClean

Reputation: 14485

Perhaps surprisingly, the Bailey-Borwein-Plouffe formula gives an incremental procedure for computing the next binary or hexadecimal digit of pi without needing to store all the previous digits.

Upvotes: 2

infinitesimal
infinitesimal

Reputation: 11

Here is a good article on how to represent infinite digits.

http://dobbscodetalk.com/index.php?option=com_myblog&show=Basic-Arithmetic-with-Infinite-Integers.html&Itemid=29

good luck

Upvotes: 1

Freddy
Freddy

Reputation: 3274

You could try the old method of mantissa. Basically you could have an 64 bit integer for storing the number and then a 64 bit integer for storing the exponent (which could be negative). You could build your own object type and overload the arithmetic operators, so it will be treated as a single number. It will require some work, but I think it will be your best option.

Upvotes: 3

RaYell
RaYell

Reputation: 70414

You can use decimal type which gives you 28-29 significant digits

Upvotes: 1

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