CODEWITHSUNDEEP
phpjqueryget
Edivad
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Reputation: 31

Send string from php to js file using jquery

i need to get the string from on php file someone know how can i do this?

My.php that write and read contenute of one file

<?php
 $dir = '/var/www/devData/test';

 // create new directory with 777 permissions if it does not exist yet
 // owner will be the user/group the PHP script is run under
 if ( !file_exists($dir) ) {
  mkdir ($dir, 0777);
 }
 if (isset($_POST['data'])) {

         $stringData = $_POST['data'];
         $file = "/var/www/devData/test/ciao.txt"; 
         $fh = fopen($file, 'r+') or die("can't open file");
         fwrite($fh, $stringData);
         $theData = fread($fh, filesize($myFile)); //this is the string that i have to pass
         fclose($fh); 

         return $theData;

 }


 ?>

my.js scrpt that use the methode get for retrive the strng from my php file

 function addLabelCustom_options() {
  var select = document.getElementById('label_custom');

 $.get("JS/foo.php", function(result){ alert(result) }, "json");


 /* $.ajax({
  url:'/var/www/devData/test/ciao.txt',
  success: function (data){
  //parse ur data
  //you can split into lines using data.split('\n') 
  //use regex functions to effectivley parse
  var label_parsed = data.splitCSV();
    select.options[0] = new Option("-- Select Label --",0);
    var label_sort = new Array();

    for (var i=0; i<label_parsed.length-1; i++)
        label_sort.push(label_parsed[i][1]);

    label_sort.sort();
    for (var j=0; j<label_sort.length-1; j++)
        select.options[j+1] = new Option(label_sort[j],j+1);

}
});

*/
}

i Just need to get the contenute of the string $theData Looks like if i don't retrive any string....

Upvotes: 0

Views: 321

Answers (3)

Edivad
Edivad

Reputation: 31

Guys i solved the problem like every time is stupid thing and every time i understand that i'm really stupid however i post the solution.

firs php file used for create a dir and store on file 

<?php
 $dir = '/var/www/devData/test';

 // create new directory with 777 permissions if it does not exist yet
 // owner will be the user/group the PHP script is run under
 if ( !file_exists($dir) ) {
  mkdir ($dir, 0777);
 }
 if (isset($_POST['data'])) {

         $stringData = $_POST['data'];
         $file = "/var/www/devData/test/ciao.txt"; 
         $fh = fopen($file, 'r+') or die("can't open file");
         fwrite($fh, $stringData);
         $theData = fread($fh, filesize($file));
         fclose($fh); 

        echo json_encode($theData);
 }


 ?>

For read the contenute i create another file php 

<?php


        $file = "/var/www/devData/test/ciao.txt"; 
            $fh = fopen($file, 'r') or die("can't open file");
        $theData = fread($fh, filesize($file));<--- was the error before i used Myfile but that variable wasn't declare and was empty :) lol 
        fclose($fh); 

        echo json_encode($theData);


 ?>

thanks to everybody !!

Upvotes: 0

Sumit Neema
Sumit Neema

Reputation: 480

After echo the content in php function (echo $theData; ) try the following jquery code

$.ajax({
 url:JS/foo.php,
 success:function(result){ alert(result) }, "json"),
 error:function(alert('Not Completed'))
};

And also check the response in the console to check for any errors.You can view the console of F12 in firefox

Upvotes: 0

user657496
user657496

Reputation: 

<?php
 $dir = '/var/www/devData/test';

 // create new directory with 777 permissions if it does not exist yet
 // owner will be the user/group the PHP script is run under
 if ( !file_exists($dir) ) {
  mkdir ($dir, 0777);
 }
 if (isset($_POST['data'])) {

         $stringData = $_POST['data'];
         $file = "/var/www/devData/test/ciao.txt"; 
         $fh = fopen($file, 'r+') or die("can't open file");
         fwrite($fh, $stringData);
         $theData = fread($fh, filesize($myFile)); //this is the string that i have to pass
         fclose($fh); 

         echo $theData;  // <-- ECHO

 }


 ?>

You have to OUTPUT the data, not return it. That is, echo it. If the string is not yet json encoded, use echo json_encode($theData);

Upvotes: 1

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