CODEWITHSUNDEEP
android
hemanth kumar
hemanth kumar

Reputation: 3078

How to set the image from drawable dynamically in android?

I am storing my project related images in drawable folder. Also I am storing the image names in string variable and dynamically I am trying to set those images to the imageview. But the image is not displaying. Please help me in this regard.

My Code:

int res = getResources().getIdentifier(imagename, "drawable", this.getPackageName());
imageview= (ImageView)findViewById(R.id.imageView);
imageview.setImageResource(res);

In the above code "imagename" is the string variable which contains the image name.

Upvotes: 82

Views: 259246

Answers (17)

simpi
simpi

Reputation: 81

set in ImageView like this : imageView.setImageResource(R.drawable.image)

Upvotes: 8

Osama Remlawi
Osama Remlawi

Reputation: 2990

Here is how to do it in Kotlin, inside a loop i:

Code reused from rfsbraz 's answer

    val uri = "@drawable/pic_top${i+1}"
    val imageResource = activity.resources.getIdentifier(uri, null, activity.packageName)

    val res = activity.getResources().getDrawable(imageResource)
    holder.view.imgDigit.setImageDrawable(res)

Upvotes: 2

Shashank Pandey
Shashank Pandey

Reputation: 778

ImageView imageView=findViewById(R.id.imageView)

if you have image in drawable folder then use

imageView.setImageResource(R.drawable.imageView)

if you have uri and want to display it in imageView then use

imageView.setImageUri("uri")

if you have bitmap and want to display it in imageView then use

imageView.setImageBitmap(bitmap)

note:- 1. imageView.setImageDrawable() is now deprecated in java 2. If image uri is from firebase or from any other online link then use

    Picasso.get()
    .load("uri")
    .into(imageView)

(https://github.com/square/picasso)

or use

Glide.with(context)
            .load("uri")
            .into(imageView)

(https://github.com/bumptech/glide)

Upvotes: 7

Georgy Gobozov
Georgy Gobozov

Reputation: 13731

imageview= (ImageView)findViewById(R.id.imageView);
imageview.setImageResource(R.drawable.mydrawable);

Upvotes: 43

Anand
Anand

Reputation: 71

int[] phptr=new int[5];

adding image pointer to array 

for(int lv=0;lv<3;lv++)
    {
        String id="a"+String.valueOf(lv+1);
        phptr[lv]= getResources().getIdentifier(id, "drawable", getPackageName());
    }

for(int loopvariable=0;loopvariable<3;loopvariable++) 
    {
        et[loopvariable] = findViewById(p[loopvariable]);
    }



for(int lv=0;lv<3;lv++)
    {
        et[k].setImageResource(phptr[k]);
    }

Upvotes: 1

Faustino Gagneten
Faustino Gagneten

Reputation: 2774

Here is the best way that works in every phone at today. Most of those answer are deprecated or need an API >= 19 or 22. You can use the fragment code or the activity code depends what you need.

Fragment

//setting the bitmap from the drawable folder
Bitmap bitmap= BitmapFactory.decodeResource(getActivity().getResources(), R.drawable.my_image);

//set the image to the imageView
imageView.setImageBitmap(bitmap);

Activity

//setting the bitmap from the drawable folder
Bitmap bitmap= BitmapFactory.decodeResource(MyActivity.this.getResources(), R.drawable.my_image);

//set the image to the imageView
imageView.setImageBitmap(bitmap);

Cheers!

Upvotes: 6

emilpmp
emilpmp

Reputation: 1736

getDrawable() is deprecated, so try this

imageView.setImageResource(R.drawable.fileName)

Upvotes: 3

Abdul Rizwan
Abdul Rizwan

Reputation: 4108

getDrawable() is deprecated. now you can use 

imageView.setImageDrawable(ContextCompat.getDrawable(this,R.drawable.msg_status_client_read))

Upvotes: 2

sohelpme
sohelpme

Reputation: 145

As of API 22, getResources().getDrawable() is deprecated (see also Android getResources().getDrawable() deprecated API 22). Here is a new way to set the image resource dynamically:

String resourceId = "@drawable/myResourceName"; // where myResourceName is the name of your resource file, minus the file extension
int imageResource = getResources().getIdentifier(resourceId, null, getPackageName());
Drawable drawable = ContextCompat.getDrawable(this, imageResource); // For API 21+, gets a drawable styled for theme of passed Context
imageview = (ImageView) findViewById(R.id.imageView);
imageview.setImageDrawable(drawable);

Upvotes: 2

rfsbraz
rfsbraz

Reputation: 2111

Try this:

String uri = "@drawable/myresource";  // where myresource (without the extension) is the file

int imageResource = getResources().getIdentifier(uri, null, getPackageName());

imageview= (ImageView)findViewById(R.id.imageView);
Drawable res = getResources().getDrawable(imageResource);
imageView.setImageDrawable(res);

Upvotes: 146

Parag Kadam
Parag Kadam

Reputation: 3850

This works fine for me.

final R.drawable drawableResources = new R.drawable(); 
final Class<R.drawable> c = R.drawable.class;
final Field[] fields = c.getDeclaredFields();
for (int i=0; i < fields.length;i++) 
{
     resourceId[i] = fields[i].getInt(drawableResources);  
    /* till here you get all the images into the int array resourceId.*/
}
imageview= (ImageView)findViewById(R.id.imageView);
if(your condition)
{
   imageview.setImageResource(resourceId[any]);
}

Upvotes: 0

Karan Datwani
Karan Datwani

Reputation: 795

imageView.setImageResource(R.drawable.picname);

Upvotes: 3

cmcoffee91
cmcoffee91

Reputation: 151

This works for me (dont use the extension of the image, just the name):

String imagename = "myImage";
int res = getResources().getIdentifier(imagename, "drawable", this.getPackageName());
imageview= (ImageView)findViewById(R.id.imageView);
imageview.setImageResource(res);

Upvotes: 7

Venky
Venky

Reputation: 11107

First of let's your image name is myimage. So what you have to do is that go to Drawable and save the image name myimage.

Now assume you know only image name and you need to access it. Use below snippet to access it,

what you did is correct , ensure you saved image name you are going to use inside coding.

public static int getResourceId(Context context, String name, String resourceType) {
    return context.getResources().getIdentifier(toResourceString(name), resourceType, context.getPackageName());
}

private static String toResourceString(String name) {
    return name.replace("(", "")
               .replace(")", "")
               .replace(" ", "_")
               .replace("-", "_")
               .replace("'", "")
               .replace("&", "")
               .toLowerCase();
}

In addition to it you should ensure that there is no empty spaces and case sensitives

Upvotes: 2

Chintan Raghwani
Chintan Raghwani

Reputation: 3370

Try this Dynamic code

String fnm = "cat"; //  this is image file name
String PACKAGE_NAME = getApplicationContext().getPackageName();
int imgId = getResources().getIdentifier(PACKAGE_NAME+":drawable/"+fnm , null, null);
System.out.println("IMG ID :: "+imgId);
System.out.println("PACKAGE_NAME :: "+PACKAGE_NAME);
//    Bitmap bitmap = BitmapFactory.decodeResource(getResources(),imgId);
your_image_view.setImageBitmap(BitmapFactory.decodeResource(getResources(),imgId));

In above code you will need Image-file-Name and Image-View object which both you are having.

Upvotes: 23

Nirali
Nirali

Reputation: 13825

See below code this is working for me

iv.setImageResource(getResources().getIdentifier(
                "imagename", "drawable", "com.package.application"));

Upvotes: 8

Ram kiran Pachigolla
Ram kiran Pachigolla

Reputation: 21201

Here i am setting the frnd_inactive image from drawable to the image

 imageview= (ImageView)findViewById(R.id.imageView);
 imageview.setImageDrawable(getResources().getDrawable(R.drawable.frnd_inactive));

Upvotes: 45

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