Reputation: 41
This is somewhat of a continuation of an earlier question. I have figured out how to use a selector to point to a specific ID and look for a value="", and then fill that with a red background... i.e. -
$('[id^="f04"][value=""]').css('background-color', 'red')
What I need to do now is build on this so it looks at f04, f05, and f06 for value=""... Any ideas on how to write that? I've tried several different ways to no avail.
Upvotes: 3
Views: 86
Reputation: 50201
You use exactly what you would use with a CSS selector: commas:
$('#f04, #f05, #f06').filter('[value=""]').css('background-color', 'red');
or the more awkward:
$('#f04:[value=""], #f05:[value=""], #f06:[value=""]')
.css('background-color', 'red');
Upvotes: 2
Reputation: 34107
To get all the elements starting with "f0" you should use:
$("[id^=f0]")
To get those that end with "f0"
$("[id$=f0]")
In your case something like this :)
$('[id^="f0"][value=""]').css('background-color', 'red')
See also the JQuery documentation
Upvotes: 2
Reputation: 191729
Very easy .. just change f04
to f0
in that selector. The ^=
operator just means "begins with."
If it goes up to 10 or higher then I guses just ^=f
will have to do.
Upvotes: 5