CODEWITHSUNDEEP
javascript
Milos Cuculovic
Milos Cuculovic

Reputation: 20223

Javascript function is not executed each time when called

I have a javascript function which is called from another function I have.

For some reasons, this function is not executed each time when called. I have tryed to change the name of the function, and then everything works fine.

I don't understand why. Here is a litle example:

javascript 1:

function a()
{ 
   b();
}

javascript 2:

function b()
{ 
   c();
}

javascript 3:

function c()
{ 
   alert("Function c");
}

The function c is not executed for some reasons... If for example the function c will be called newC(), then it works fine.

Upvotes: 1

Views: 3088

Answers (2)

Praveen Singh
Praveen Singh

Reputation: 542

For me it works fine. May be you have some error in the code. IF u post the full code i may able to help. here is the working code

<html>
<head>
<script type="text/javascript">
function a()
{
b();
}
function b()
{
c();
}
function c()
{
alert("hello");
}
</script>
</head>
<body>
<form>
<label>Hello</label>
<button onclick="a()">v</button>
</form>
</body>
</html>

Upvotes: 1

Aaron Digulla
Aaron Digulla

Reputation: 328556

You probably have a conflict of names in the scope of b() i.e. when b() is executed, it can happen that c is defined to something else in a current scope.

Solution: Start your JavaScript debugger, set a breakpoint in b() and check what c is at that time.

Upvotes: 5

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