XML transformation with XSL

Question

I want to transfer XML file to other XML with XSLT. I want to do transformation because XML file isn't pure tree-structured document.

Here's my file before:

<uglyStartTag></uglyStartTag>
    <name>content</name>
<uglyEndTag></uglyEndTag>

or

<uglyStartTag/>
    <name>content</name>
<uglyEndTag/>

Here's my file after:

<beautyTag>
    <name>content</name>
</beautyTag>

How can I do it? I'm not familiarized with XSLT so I will be thankful for any advice.

Answer 1

This transformation:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
     <xsl:output omit-xml-declaration="yes" indent="yes"/>
     <xsl:strip-space elements="*"/>

     <xsl:template match=
      "node()[preceding-sibling::uglyStartTag
            and
              following-sibling::uglyEndTag
              ][1]">
      <beautyTag>
        <xsl:copy-of select=
         "../node()[preceding-sibling::uglyStartTag
                  and
                    following-sibling::uglyEndTag
                   ]
         "/>
      </beautyTag>
     </xsl:template>
</xsl:stylesheet>

when applied on this XML document (provided by the OP in a comment):

<t>
    <uglyStartTag />
    <name>dgsdgsdgsdg</name>
    <uglyEndTag />
</t>

produces the wanted, correct result:

<beautyTag>
   <name>dgsdgsdgsdg</name>
</beautyTag>