CODEWITHSUNDEEP
prolog
Lilz
Lilz

Reputation: 4091

Prolog four of a kind poker

I am trying to code a poker game using Prolog. I understand how to code the royal flush but my four of a kind code won't work.

I have the following code:

four_of_a_kind(R):-
member(card(V, T1), R),
member(card(V, T2), R),
member(card(V, T3), R),
member(card(V, T4), R).

where V is the rank which I want to be the same and T1,T2,T3,T4 are the suits. R is my list of cards.

Can anyone explain how to code the four of a kind in prolog please and explain what I am doing wrong please?

Upvotes: 1

Views: 386

Answers (1)

Haile
Haile

Reputation: 3180

Your problem is that you search the whole hand all the times and T1, T2.. are free variables, so

member(card(V, T1), R),
...

unifies 4 times with the same card, and four_of_a_kind always returns true.

Solution: Just lock the suits.

Code:

is_card(X,Y) :-
    number(X), between(1,13,X),
    member(Y, [c,d,h,s]). /* clubs, diamonds, hearts and spades */

four_of_a_kind(R) :-
    member(card(V,c), R),
    member(card(V,d), R),
    member(card(V,h), R),
    member(card(V,s), R), !.

Some query:

?- four_of_a_kind([card(7,c), card(7,d), card(7,h), card(9,s), card(7,s)]).
true.

?- four_of_a_kind([card(7,c), card(7,d), card(9,h), card(9,s), card(7,s)]).
false.

Upvotes: 2

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