CODEWITHSUNDEEP
djangosignals
Bastian
Bastian

Reputation: 5855

Is Django post_save signal asynchronous?

I have a like function which is just like social networks like or thumbs up function; the user clicks the star / heart / whatever to mark the content as liked.It is done with ajax and must be fast.

The only problem here is that for some reasons I have to do some tasks for each like and I found out they were coded straight in the like view and it makes it slow.

I am thinking of using signals to make the execution of these tasks asynchronous so the view can send back the json right away to the javascript without waiting for the tasks to finish.

I started creating a signal for the like but then realized that Django's signals were not asynchronous and it would end up the same, the view would have to wait for the signal to finish to send back its response.

So I could try to make that signal asynchronous as it is explained here and there but I would as well use the post_save signal for the like model but now I wonder if the view can finish before the signal gets executed?

Upvotes: 55

Views: 25522

Answers (4)

Chris Johnson
Chris Johnson

Reputation: 21956

The async-signals package (https://github.com/nyergler/async-signals) abstracts this issue. You call an async signal function; if Celery is present the package uses it to issue the signal asynchronously from a worker; and if Celery is not available the package sends the signal in the traditional synchronous way.

Upvotes: 4

Bouke
Bouke

Reputation: 12138

Also look into celery (or more specifically django-celery). It is an async task scheduler / handler. So your post_save signal handler creates a task, which is picked up and executed through celery. That way you still have your speedy application, while the heavy lifting is performed async, even on a different machine or batch of machines.

Upvotes: 54

Chris Pratt
Chris Pratt

Reputation: 239300

What you want is a thread. They're very easy to use. You just subclass threading.Thread and write a run method:

import threading

class LikeThread(threading.Thread):
    def __init__(self, user, liked, **kwargs):
        self.user = user
        self.liked = liked
        super(LikeThread, self).__init__(**kwargs)

    def run(self):
        # long running code here

Then, when your ready to do the task, you fire it off with:

LikeThread(request.user, something).start()

The rest of your view code or whatever will resume and return the response, and the thread will happily do its work until it's done and then end itself.

See full documentation: http://docs.python.org/library/threading.html

Upvotes: 32

Torsten Engelbrecht
Torsten Engelbrecht

Reputation: 13496

Hm, first of all signals in Django are not asynchronous. For your particular case I think post_save is the wrong way to go. The most straightforward way is simply to fire an ajax request to view which do your like action and don't wait for the response. Instead modify your view/html directly after you fired the request.

That would of course require that you know beforehand that your user is allowed to like this item and that your request will not fail.

Upvotes: 8

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