CODEWITHSUNDEEP
javascript
Karl Humphries
Karl Humphries

Reputation: 328

If value contains one or more from array

I am trying to display a list of items...

Item A Item B Item C Item D

I can tell the code to not display any items that contain A like so:

exclusions = new Array("A")
if (v.value.indexOf(exclusions) > -1) {
}
else {
DO SOMETHING
}

Where I get stuck is if I want it to exclude more than one, like so:

exclusions = new Array("A", "B")
if (v.value.indexOf(exclusions) > -1) {
}
else {
DO SOMETHING
}

Upvotes: 0

Views: 140

Answers (3)

hvgotcodes
hvgotcodes

Reputation: 120188

One way would be to use a regex. 

var matches = "there is a boy".match(/[ab]/);
if (matches === null) {
   // neither a nor b was present
}

If you need to construct a regex from strings, you can do it like 

var matches = "there is a boy".match(new RegExp("[ab]"));

If you have an array of strings like ['a', 'b'] then you need to do something like

var pattern = yourArray.join('');
var regex = new RexExp(pattern);

here we construct a string which is a pattern, and then create a new regex based on that pattern.

Upvotes: 2

Felix Kling
Felix Kling

Reputation: 816404

Here is a different way of using indexOf, utilising Array#every [MDN]:

var val = v.value;
if(exclusions.every(function(x) { return val.indexOf(x) === -1 })) {
    // val does not contain any string in `exclusions`
}

Upvotes: 1

ChristopheD
ChristopheD

Reputation: 116147

Answering in pseudo - code fashion:

exclusions = new Array("A", "B");
exclusion_found = false;
for (int i=0; i< exclusions.length; i++) {
    if (v.value.indexOf(exclusions[i]) > -1) {
        exclusion_found = true;
        break;
    }
}
if (!exclusion_found) {
    DO SOMETHING
}

Upvotes: 1

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