CODEWITHSUNDEEP
scalaimplicitscala-2.10
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Reputation: 67280

How to use Scala 2.10 implicit classes

I thought this would be correct usage of the new implicit classes of Scala 2.10:

implicit case class IntOps(i: Int) extends AnyVal {
  def twice = i * 2
}

11.twice

Apparently not:

<console>:13: error: value twice is not a member of Int
              11.twice
                 ^

Am I missing something (Scala 2.10.0-M6)?

Upvotes: 13

Views: 6236

Answers (2)

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0__

Reputation: 67280

This shows there is an ambiguity:

val ops: IntOps = 11

<console>:11: error: ambiguous reference to overloaded definition,
both method IntOps of type (i: Int)IntOps
and  object IntOps of type IntOps.type
match argument types (Int) and expected result type IntOps
       val ops: IntOps = 11
                         ^

Not sure what exactly happens. But when not using a case class it seems fine:

implicit class IntOps(val i: Int) extends AnyVal {
  def twice = i * 2
}

11.twice  // ok

Upvotes: 2

Nicolas
Nicolas

Reputation: 24769

A clue is the desugaring of implicit classes, explained in the SIP-13:

implicit class RichInt(n: Int) extends Ordered[Int] {
def min(m: Int): Int = if (n <= m) n else m
...
}

will be transformed by the compiler as follows:

class RichInt(n: Int) extends Ordered[Int] {
def min(m: Int): Int = if (n <= m) n else m
...
}
implicit final def RichInt(n: Int): RichInt = new RichInt(n)

As you can see, the implicit function that is created has the same name as the original classes. I guess it's done like this to make implicit classes easier to import.

Thus in your case, when you create an implicit case class, there is a conflict between the method name created by the implicit keyword and the companion object created by the case keyword.

Upvotes: 20

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