CODEWITHSUNDEEP
scaladata-structureslanguage-designvariadic-functions
Andrea
Andrea

Reputation: 20493

Scala variadic functions and Seq

As far as I know, traits like List or Seq are implemented in the Scala standard library instead of being part of the language itself.

There is one thing that I do not understand, though: one has a syntax for variadic functions that looks like

def foo(args: String*) = ...

Internally one has access to args and it will be a Seq.

It is not clear to me whether:

Does anyone know which one is the correct intepretation?

Upvotes: 14

Views: 4486

Answers (2)

0__
0__

Reputation: 67290

It is indeed somewhat a 'blur' between language and library. The Scala Language Specification v2.9 states in §4.6.2 Repeated Parameters:

The last value parameter of a parameter section may be suffixed by “*”, e.g. (..., x:T*). The type of such a repeated parameter inside the method is then the sequence type scala.Seq[T].

So when you use repeated arguments, it is assumed that scala.Seq is available at runtime (which should be the case, as it is part of the standard library).

Upvotes: 15

Jens Schauder
Jens Schauder

Reputation: 81930

I think it is the first one. There are a couple of types that the language demands to exist although they aren't really part of the language. With Seq you found one.

Upvotes: 2

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