CODEWITHSUNDEEP
matlabmatrix
user1597969
user1597969

Reputation: 405

Replace values in matrix with other values

I have a matrix with integers and I need to replace all appearances of 2 with -5. What is the most efficient way to do it? I made it the way below, but I am sure there is more elegant way.

a=[1,2,3;1,3,5;2,2,2]
ind_plain = find(a == 2)
[row_indx col_indx] = ind2sub(size(a), ind_plain)
for el_id=1:length(row_indx)
    a(row_indx(el_id),col_indx(el_id)) = -5;
end

Instead of loop I I seek for something like: a(row_indx,col_indx) = -5, which does not work.

Upvotes: 14

Views: 60004

Answers (4)

Timmmm
Timmmm

Reputation: 97148

Here's a trivial, unoptimised, probably slow implementation of changem from the Mapping Toolbox.

function mapout = changem(Z, newcode, oldcode)
% Idential to the Mapping Toolbox's changem
% Note the weird order: newcode, oldcode. I left it unchanged from Matlab.
    if numel(newcode) ~= numel(oldcode)
        error('newcode and oldcode must be equal length');
    end

    mapout = Z;

    for ii = 1:numel(oldcode)
        mapout(Z == oldcode(ii)) = newcode(ii);
    end
end

Upvotes: 0

Andrey Rubshtein
Andrey Rubshtein

Reputation: 20915

find is not needed in this case. Use logical indexing instead:

a(a == 2) = -5

In case of searching whether a matrix is equal to inf you should use

a(isinf(a)) = -5

The general case is:

Mat(boolMask) = val

where Mat is your matrix, boolMask is another matrix of logical values, and val is the assignment value

Upvotes: 28

Palli
Palli

Reputation: 680

The Martin B's method is good if you are changing values in vector. However, to use it in matrix you need to get linear indices.

The easiest solution I found is to use changem function. Very easy to use:

mapout = changem(Z,newcode,oldcode) In your case: newA = changem(a, 5, -2)

More info: http://www.mathworks.com/help/map/ref/changem.html

Upvotes: 1

Martin B
Martin B

Reputation: 24180

Try this:

a(a==2) = -5;

The somewhat longer version would be

ind_plain = find(a == 2);
a(ind_plain) = -5;

In other words, you can index a matrix directly using linear indexes, no need to convert them using ind2sub -- very useful! But as demonstrated above, you can get even shorter if you index the matrix using a boolean matrix.

By the way, you should put semicolons after your statements if (as is usually the case) you're not interested in getting the result of the statement dumped out to the console.

Upvotes: 13

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