CODEWITHSUNDEEP
php
sanny Sin
sanny Sin

Reputation: 1555

Returning array elements according to their types

I'm reading book about php, and here is task to print elements of array depends on their type; So i created array $arr = array (5, 'str', 4, 'str1', -100, 10);, and then using foreach statement i tried to print elements that are integer 

foreach ($arr1 as is_integer($arrelem)) 
    {
        print $arrelem;

    }

But this gives me an errorFatal error: Can't use function return value in write context in. I'm sure there is something wrong with algorithm, but i need advice on how to understand these alhorighms

Upvotes: 0

Views: 76

Answers (4)

Baba
Baba

Reputation: 95101

You can use this example 

$arr = array(5,'str',4,'str1',- 100,10);

Example 1 - Waygood 

foreach ($arr as $var) {
    print $var . ": ";
    echo gettype($var), "\n";
}

Example 2 

foreach ( $arr as $var ) {
    print $var . ": ";
    if (is_integer($var)) {
        if ($var < 0) {
            print "Negative Integer \n";
        } else {
            print "Positive Integer \n";
        }
    }
}

Upvotes: 0

Mark Baker
Mark Baker

Reputation: 212412

$integerValues = array_filter($array1,'is_integer');
$booleanValues = array_filter($array1,'is_bool');

etc

Upvotes: 3

Halcyon
Halcyon

Reputation: 57709

foreach ($arr1 as is_integer($arrelem)) is not allowed

Write it like so:

foreach ($arr1 as $arrelem) {
    if (is_integer($arrelem)) {
        print "int:" . $arrelem;
    } else if (is_string($arrelem)) {
        print "string:" . $arrelem;
    } else {
        print "other:" . $arrelem;
    }
}

If this is for debugging you can also use var_dump, which will give you the type and value of a variable.

Upvotes: 5

Danil Speransky
Danil Speransky

Reputation: 30453

It is not correct syntax, after keyword as you may place only name of variable.

Upvotes: 0

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