Reputation: 3668
In Python, I only want to list all the files in the current directory ONLY. I do not want files listed from any sub directory or parent.
There do seem to be similar solutions out there, but they don't seem to work for me. Here's my code snippet:
import os
for subdir, dirs, files in os.walk('./'):
for file in files:
do some stuff
print file
Let's suppose I have 2 files, holygrail.py and Tim inside my current directory. I have a folder as well and it contains two files - let's call them Arthur and Lancelot - inside it. When I run the script, this is what I get:
holygrail.py
Tim
Arthur
Lancelot
I am happy with holygrail.py and Tim. But the two files, Arthur and Lancelot, I do not want listed.
Upvotes: 337
Views: 602173
Reputation: 56
Following up on Pygirl and Flimm, use of pathlib, (really helpful reference, btw) their solution included the full path in the result, so here is a solution that outputs just the file names:
from pathlib import Path
p = Path(destination_dir) # destination_dir = './' in original post
files = [x.name for x in p.iterdir() if x.is_file()]
print(files)
Upvotes: 1
Reputation: 1904
To list files in a specific folder excluding files in its sub-folders with os.walk
use:
_, _, file_list = next(os.walk(data_folder))
Upvotes: 0
Reputation: 101142
Just use os.listdir
and os.path.isfile
instead of os.walk
.
Example:
import os
files = [f for f in os.listdir('.') if os.path.isfile(f)]
for f in files:
# do something
But be careful while applying this to other directory, like
files = [f for f in os.listdir(somedir) if os.path.isfile(f)]
which would not work because f
is not a full path but relative to the current directory.
Therefore, for filtering on another directory, do os.path.isfile(os.path.join(somedir, f))
(Thanks Causality for the hint)
Upvotes: 552
Reputation: 13349
You can use the pathlib
module.
from pathlib import Path
x = Path('./')
print(list(filter(lambda y:y.is_file(), x.iterdir())))
Upvotes: 16
Reputation: 310097
You can use os.listdir
for this purpose. If you only want files and not directories, you can filter the results using os.path.isfile
.
example:
files = os.listdir(os.curdir) #files and directories
or
files = filter(os.path.isfile, os.listdir( os.curdir ) ) # files only
files = [ f for f in os.listdir( os.curdir ) if os.path.isfile(f) ] #list comprehension version.
Upvotes: 92
Reputation: 890
import os
for subdir, dirs, files in os.walk('./'):
for file in files:
do some stuff
print file
You can improve this code with del dirs[:]
which will be like following .
import os
for subdir, dirs, files in os.walk('./'):
del dirs[:]
for file in files:
do some stuff
print file
Or even better if you could point os.walk with current working directory .
import os
cwd = os.getcwd()
for subdir, dirs, files in os.walk(cwd, topdown=True):
del dirs[:] # remove the sub directories.
for file in files:
do some stuff
print file
Upvotes: 5
Reputation: 564
this can be done with os.walk()
python 3.5.2 tested;
import os
for root, dirs, files in os.walk('.', topdown=True):
dirs.clear() #with topdown true, this will prevent walk from going into subs
for file in files:
#do some stuff
print(file)
remove the dirs.clear() line and the files in sub folders are included again.
update with references;
os.walk documented here and talks about the triple list being created and topdown effects.
.clear() documented here for emptying a list
so by clearing the relevant list from os.walk you can effect its result to your needs.
Upvotes: 7
Reputation: 2876
You can use os.scandir()
. New function in stdlib starts from Python 3.5.
import os
for entry in os.scandir('.'):
if entry.is_file():
print(entry.name)
Faster than os.listdir()
. os.walk()
implements os.scandir()
.
Upvotes: 19
Reputation: 647
import os
destdir = '/var/tmp/testdir'
files = [ f for f in os.listdir(destdir) if os.path.isfile(os.path.join(destdir,f)) ]
Upvotes: 30