CODEWITHSUNDEEP
iphoneiospropertiesnsarrayivar
user1010563
user1010563

Reputation:

iOS - How to access object properties in an array properly?

Setup:

ViewController holds an MyArray of objects from the PersonClass. PersonClass has just two properties: name and age.

Problem:

When I want to read out a name property from the first object in MyArray whats the proper way to do this?

Do I have to temporarily create an instance of PersonClass like this?

PersonClass *tmp = [PersonClass alloc] init];
tmp = [MyArray objectAtIndex:0];

NSLog(@"%@", tmp.name);

Or can I refer directly to the properties of the objects in the MyArray?

Something like this:

 NSLog(@"%@", [self.contactsArray objectAtIndex:0].name); // not working

Upvotes: 1

Views: 2559

Answers (5)

justin
justin

Reputation: 104718

if you want or need the type to be present, then introduce the type like so:

PersonClass * person = [array objectAtIndex:0];

i do this quite regularly for readability, and because included files' declarations can otherwise break things.

note that the cast is not required when assigning an objc variable from an id value.

Do I have to temporarily create an instance of PersonClass?

No. The program you wrote creates a temporary which is never used.

Upvotes: 0

Bartosz Ciechanowski
Bartosz Ciechanowski

Reputation: 10333

I'd strongly advise using

[(PersonClass *)[MyArray objectAtIndex:0] name]

instead of seemingly cleaner, but troublesome form

[[MyArray objectAtIndex:0] name]

There are two reasons for this. First of all, it's explicit for the reader what gets called on which object. Secondly, it's explicit for the compiler - if two methods share the same name, but different return values things can get nasty. Matt Gallagher at Cocoa With Love has an excellent explanation of this issue.

Upvotes: 6

Nick Bull
Nick Bull

Reputation: 4286

Do I have to temporarily create an instance of PersonClass like this?

PersonClass *tmp = [PersonClass alloc] init];
tmp = [MyArray objectAtIndex:0];

NSLog(@"%@", tmp.name);

No. Just use

PersonClass *tmp = (PersonClass *)[myArray objectAtIndex:0];
NSLog(@"%@", tmp.name);

As the object you are getting from myArray is (or should be!) already alloc'd and init'd before being added to the array. The things in the array are pointers to objects. That's what you are passing around. You have to tell it which type of object you have in there though (the cast is (PersonClass *)) because NSArray just stores NSObjects.

You could also do it in one line as thus

((PersonClass *)[myArray objectAtIndex:0]).name;

Upvotes: 0

Andrey Chernukha
Andrey Chernukha

Reputation: 21818

((PersonClass *)[MyArray objectAtIndex:0]).name

or just [[MyArray objectAtIndex:0] name]

Upvotes: 0

Nosrettap
Nosrettap

Reputation: 11340

You can do this

PersonClass *tmp = (PersonClass *) [MyArray objectAtIndex:0];
NSLog(@"%@",tmp.name);

Or we can put this on just one line:

NSLog(@"%@",((PersonClass *)[MyArray objectatIndex:0]).name);

The reason that NSLog(@"%@", [self.contactsArray objectAtIndex:0].name); doesn't work is you haven't told the compiler what type of object is at [self.contactsArray objectAtIndex:0]. Because it doesn't know what type of object is in your array, there is no way for it to know that it has a name property

Upvotes: 0

Related Questions