Reputation: 59
How do I able to get which day by input date?
Input Date example: 15-08-2012
How do I know if its monday, tuesday or which day using C++.
I am trying to omit out weekends from the date available of a month, so If i input e.g the month of August 2012, i want to check which day is saturday and which day is sunday, so i can omit it out from the available date for my program.
Code that I tried for getting the amount of days in a month:
if (month == 4 || month == 6 || month == 9 || month == 11)
{
maxDay = 30;
}
else if (month == 2)
//{
// bool isLeapYear = (year% 4 == 0 && year % 100 != 0) || (year % 400 == 0);
// if (isLeapYear)
// {
// maxDay = 29;
// }
//else
{
maxDay = 28;
}
The next thing i want to know is in that month, which day are weekend so i can omit that from result.
Upvotes: 3
Views: 19847
Reputation: 1584
Here is a simpler and probably better implementation as it does not need any extra library imports. The result returned is an int from 0 to 6 (Sunday, Mon, Tue... Saturday).
#include <iostream>
int dayofweek(int d, int m, int y){
static int t[] = { 0, 3, 2, 5, 0, 3, 5, 1, 4, 6, 2, 4 };
y -= m < 3;
return ( y + y/4 - y/100 + y/400 + t[m-1] + d) % 7;
}
/* Driver function to test above function */
int main(){
int day = dayofweek(23, 10, 2013);
// Above statement finds the week day for 10/23/2013
//dayofweek(<day in month>,<month>,<year>)
std::cout << day;
return 0;
}
Upvotes: 2
Reputation: 477140
You should use mktime
and ctime
and extract the tm_wday
field of the tm
structure. It is guaranteed that mktime
doesn't require that field, so you can populate a skeleton tm
structure, process it and decompose it back into a complete structure:
#include <ctime>
std::tm t = {};
t.tm_mday = 15;
t.tm_mon = 8;
t.tm_year = 2012;
std::tm * p = std::localtime(std::mktime(&t));
// result is p->tm_wday
Upvotes: 1
Reputation: 153929
I'd use mktime()
. Given day, month and year, fill out a tm
, then
call mktime
on it:
tm timeStruct = {};
timeStruct.tm_year = year - 1900;
timeStruct.tm_mon = month - 1;
timeStruct.tm_mday = day;
timeStruct.tm_hour = 12; // To avoid any doubts about summer time, etc.
mktime( &timeStruct );
return timeStruct.tm_wday; // 0...6 for Sunday...Saturday
Upvotes: 3
Reputation: 97958
#include <stdio.h>
#include <time.h>
int main ()
{
char *str = "15-08-2012";
struct tm tm;
if (strptime (str, "%d-%m-%Y", &tm) == NULL) {
/* Bad format !! */
}
char buffer [80];
strftime (buffer, 80, "Day is %a", &tm);
puts (buffer);
return 0;
}
Upvotes: 0
Reputation: 1791
#include <ctime>
std::tm time_in = { 0, 0, 0, // second, minute, hour
4, 9, 1984 - 1900 }; // 1-based day, 0-based month, year since 1900
std::time_t time_temp = std::mktime( & time_in );
// the return value from localtime is a static global - do not call
// this function from more than one thread!
std::tm const *time_out = std::localtime( & time_temp );
std::cout << "I was born on (Sunday = 0) D.O.W. " << time_out->tm_wday << '\n';
Date to Day of the week algorithm?
Upvotes: 5