Reputation: 17553
Say I have a specific instant in time where I know the hour, minute, day, second, month, year, etc; how can I convert this epoch time (seconds since 1970)?
I can't use Boost, so please don't suggest a Boost solution.
Upvotes: 22
Views: 49455
Reputation: 896
Sample code to convert date string in some format to unix epoch time.
struct tm tm;
double dateInEpoch;
if (strptime("06 Jul 2022", "%d %b %Y", &tm)) {
time_t curTime;
struct tm * timeinfo;
time(&curTime );
timeinfo = localtime(&curTime);
timeinfo->tm_year = tm.tm_year
timeinfo->tm_mon = tm.tm_mon;
timeinfo->tm_mday = tm.tm_mday;
dateInEpoch = mktime( timeinfo );
}
For date format, please visit http://www.cplusplus.com/reference/ctime/strftime/
To test epoch date, visit https://www.epochconverter.com
Upvotes: 2
Reputation: 1717
mktime and memset is most portable for me:
struct tm t;
memset(&t, 0, sizeof(tm)); // Initalize to all 0's
t.tm_year = 112; // This is year-1900, so 112 = 2012
t.tm_mon = 8;
t.tm_mday = 15;
t.tm_hour = 21;
t.tm_min = 54;
t.tm_sec = 13;
time_t time_since_epoch = mktime(&t);
Upvotes: 0
Reputation: 91
On Linux, use timegm to avoid having your local time zone subtracted:
struct tm tm;
// set tm.tm_year, tm.tm_mon, tm.tm_mday, tm.tm_hour, tm.tm_min and tm.tm_sec
tm.tm_year -= 1900; // year start at 1900
tm.tm_mon--; // months start at january
TIME_STAMP t = timegm(&tm);
Upvotes: 8
Reputation: 400274
Use the mktime(3)
function. For example:
struct tm t = {0}; // Initalize to all 0's
t.tm_year = 112; // This is year-1900, so 112 = 2012
t.tm_mon = 8;
t.tm_mday = 15;
t.tm_hour = 21;
t.tm_min = 54;
t.tm_sec = 13;
time_t timeSinceEpoch = mktime(&t);
// Result: 1347764053
Upvotes: 38