Reputation: 343
I have just started working on php. It's a very good lang as I'm feeling but some point I get stuck as I'm new to this.
My javascript code
var pv = $("#txtStart").val();
var av = $("#txtStartNextLevel").val();
var au = $("#fileStartPlay").val();
alert(pv+" "+av+" "+au);
var myau = au.split('\\');
$.ajax({
type:"POST",
url:php_url,
data:"{startPoint:"+pv+"nextLevelPoint:"+av+"audioFile:"+myau[myau.length-1]+"}",
contentType:"application/json",
dataType:"json",
success:function(){
alert("done");
},
error:function(){
alert(response);
}
});
My PHP code.
<?php
if(file_exists("Text.txt"))
{
$fileName = "Text.txt";
$fh = fopen($fileName,"a")
$Starts = $_POST["startPoint"];
$NextLevel = $_POST["nextLevelPoint"];
$AudioFileName = $_POST["audioFile"];
$code .=$Starts."*".$NextLevel."_1*".$AudioFileName."\"";
fwrite($fh,$code);
fclose($fh);
}
?>
When I run this it executes but doesn't write the values in the variable
$Starts,$NextLevel,$AudioFileName**.
And further if I write the same ajax procedure in
$.post(php_url,{startPoint:pv,nextLevelPoint:av,audioFile:myau[myau.length-1]},function(data){});
this works fine and write the content in the file.
Also As I'm using post method it should not display the values in Address bar what I'm passing to write. But it's showing those values in both the method.
localhost://myphp.php?txtStart=Start&fileStartPlay=aceduos.jpg&txtStartNextLevel=adfd
Please guide me where I'm lacking...
Upvotes: 0
Views: 123
Reputation: 780724
Do what Burak TAMTURK said, and also get rid of
contentType:"application/json",
$_POST data should be in content-type application/x-www-form-urlencoded
, which is the default.
Upvotes: 0
Reputation: 1239
Replace the value bellow (with quotas)
"{startPoint:"+pv+"nextLevelPoint:"+av+"audioFile:"+myau[myau.length-1]+"}"
to
{startPoint:pv, nextLevelPoint: av, audioFile: myau[myau.length-1]}
Upvotes: 3