CODEWITHSUNDEEP
javaclasspath
IAmYourFaja
IAmYourFaja

Reputation: 56894

How to read a directory from the runtime classpath?

My Java application needs to be able to find a myconfig/ directory which will be bundled inside the same JAR:

myjar.jar/
    com/
        me/
            myproject/
                ConfigLoader.java --> looks for myconfig/ directory and its contents
    myconfig/
        conf-1.xml
        conf.properties
        ... etc.

How do I actually go about reading this myconfig/ directory off the runtime classpath? I've done some research and it seems that the normal method of reading a file from the classpath doesn't work for directories:

InputStream stream = ConfigLoader.class.getResourceAsStream("myconfig");

So does anyone know how to read an entire directory from the runtime classpath (as opposed to a single file)? Thanks in advance!

Please note: It is not possible to load the files individually, myconfig is a directory with thousands of properties files inside it.

Upvotes: 11

Views: 13590

Answers (4)

Huseyin
Huseyin

Reputation: 567

String path = getClass().getClassLoader().getResource("myproperties.properties").getPath();

Upvotes: -2

Thorsten
Thorsten

Reputation: 151

The trick seems to be that the class loader can find directories in the classpath, while the class can not.

So this works

this.getClass().getClassLoader().getResource("com/example/foo/myconfig");

while this does not

this.getClass().getResource("myconfig");

Upvotes: 0

maba
maba

Reputation: 48045

You can use the PathMatchingResourcePatternResolver provided by Spring.

public class SpringResourceLoader {

    public static void main(String[] args) throws IOException {
        PathMatchingResourcePatternResolver resolver = new PathMatchingResourcePatternResolver();

        // Ant-style path matching
        Resource[] resources = resolver.getResources("/myconfig/**");

        for (Resource resource : resources) {
            InputStream is = resource.getInputStream();
            ...
        }
    }
}

I didn't do anything fancy with the returned Resource but you get the picture.

Add this to your maven dependency (if using maven):

<dependency>
    <groupId>org.springframework</groupId>
    <artifactId>spring-core</artifactId>
    <version>3.1.2.RELEASE</version>
</dependency>

Upvotes: 12

Kenster
Kenster

Reputation: 25380

You could call ClassLoader.getResource() to find a particular file in the directory (or the directory itself, if getResource() will return directories). getResource() returns a URL pointing to the result. You could then convert this URL into whatever form the other library requires.

Upvotes: 5

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