Reputation: 306
I have a crontab file contains many database names such as
10 06 1 * * script DEVE_DB1
10 06 1 * * script TEST_DB1
10 06 1 * * script PROD_DB1
....
I would like to add a comment, #
, in front of TEST_DB1
in the entire file so that my cron job will not run all TEST_DB1
jobs.
I found the following script on this site,
sed -e '/TEST_DB1/, s/^/#/'
but I get an error:
sed: 0602-404 Function /TEST_DB1/, s/^/## / cannot be parsed.
Any suggestions would be greatly appreciated.
Upvotes: 3
Views: 5614
Reputation: 754420
Lose the comma (the space is optional):
sed -e '/TEST_DB1/s/^/#/'
Given the start /TEST_DB1/,
, sed
would be expecting to find the second address in a range, such as a number, $
, or another pattern. The s
doesn't fit any of these constructs, hence the error.
Upvotes: 9