Reputation: 39
Suppose I am staying in currenty directory, I wanted to list all the files in total numbers, as well as the size, permission, and also the number of files by types.
here is the sample outputs:
Here is a sample :
Print information about "/home/user/poker"
total number of file : 83
pdf files : 5
html files : 9
text files : 15
unknown : 5
NB: anyfile without extension could be consider as unknown.
i hope to use some simple command like ls, cut, sort, unique ,(just examples) put each different extension in file and using wc -l to count number of lines
or do i need to use grep, awk , or something else?
Hope to get the everybody's advices.thank you!
Upvotes: 1
Views: 485
Reputation: 57650
file
to output only mimetype and pass it to awk
.file * -ib | awk -F'[;/.]' '{print $(NF-1)}' | sort -n | uniq -c
On my home directory it produces this output.
35 directory
3 html
1 jpeg
1 octet-stream
1 pdf
32 plain
5 png
1 spreadsheet
7 symlink
1 text
1 x-c++
3 x-empty
1 xml
2 x-ms-asf
4 x-shellscript
1 x-shockwave-flash
text/x-c++
and text/plain
should be in same Use this file * -ib | awk -F'[;/.]' '{print $1}' | sort -n | uniq -c
6 application
6 image
45 inode
40 text
2 video
Change the {print $1}
part according to your need to get the appropriate output.
Upvotes: 3
Reputation: 12033
find . -type f | xargs -n1 basename | fgrep . | sed 's/.*\.//' | sort | uniq -c | sort -n
That gives you a recursive list of file extensions. If you want only the current directory add a -maxdepth 1
to the find command.
Upvotes: 0
Reputation: 798606
You need bash.
files=(*)
pdfs=(*.pdf)
echo "${#files[@]}"
echo "${#pdfs[@]}"
echo "$((${#files[@]}-${#pdfs[@]}))"
Upvotes: 0