CODEWITHSUNDEEP
phpcodeigniterassociative-array
md1hunox
md1hunox

Reputation: 3955

Illegal string offset error in codeigniter view

im doing a PHP project using codeigniter 2.1.2 , using mySql database on WAMP, i have stumbled upon the following problem:

Here is my model

function loadUserData() {
    $sql = "SELECT username FROM user WHERE username = ?";
    $query = $this -> db -> query($sql, $this->session->userdata('username'));

    if ($query -> num_rows() > 0) {
        foreach ($query->result() as $row) {
            $data = $row;
        }
        return $data;
    }

}

The controller

function profile_access() {
    if ($this -> session -> userdata('is_logged_in')) {
        $this->load-> model('profile_model');
        $uData['rows']=$this->profile_model->loadUserData();
        $this->load->view('profile_view',$uData);

    } else {
        echo "<script type=\"text/javascript\"> alert(\"You need to provide your credentials first.\");</script>";
        redirect('login_controller/index');
    }
}

and the view

<?php
      foreach($rows as $r){
              echo print_r($r);
              echo $r[username]->username; //line no. 81 in my code
            }
?>

the print_r($r) from view gives me the following errors:

alphaomega1
A PHP Error was encountered
Severity: Notice
Message: Use of undefined constant username - assumed 'username'
Filename: views/profile_view.php
Line Number: 81


A PHP Error was encountered
Severity: Warning
Message: Illegal string offset 'username'
Filename: views/profile_view.php
Line Number: 81


A PHP Error was encountered
Severity: Notice
Message: Trying to get property of non-object
Filename: views/profile_view.php
Line Number: 81

I expect the above code to return only "alphaomega" which is the username in the database. it is however displayed, but i dont know why i'm getting those errors. would appreciate some help with this. thanks.

Upvotes: 3

Views: 16199

Answers (1)

Yan Berk
Yan Berk

Reputation: 14428

In your view:

foreach($rows as $r){
     echo $r->username;
}

In your model:

function loadUserData() {
    $sql = "SELECT username FROM user WHERE username = ?";
    $query = $this->db->query($sql, $this->session->userdata('username'));

    return $query->result();
}

Upvotes: 3

Related Questions