Reputation: 26647
I'm looking at a javascript that my colleague wrote and I think that it looks like it does the same in both clauses:
function doSubmitOversikt(action, command, status) {
var checked = document.getElementById("klarbox").checked;
if(status && !checked) {
if (confirm("Ärendet är satt som Klar (formell handläggning första delen klar). Vill du verkligen ångra detta? Att ångra kan innebära att ärendet behöver arras om i CICS.")) {
document.actionForm.action.value = action;
document.actionForm.actionCommand.value = command;
document.actionForm.submit();
disableAll();
}
} else {
document.actionForm.action.value = action;
document.actionForm.actionCommand.value = command;
document.actionForm.submit();
disableAll();
}
}
What will be the difference between the above code and to unconditionally do
document.actionForm.action.value = action;
document.actionForm.actionCommand.value = command;
document.actionForm.submit();
disableAll();
?
Upvotes: 0
Views: 164
Reputation: 3597
I don't think they are one condition is if status is true and it's not checked then asked for confirmation else do nothing. If status is not true or it is checked then do.
Upvotes: 1
Reputation: 174624
The first loop will only execute if the confirmation is positive; and if the checkbox is not checked and status
is a true value.
Upvotes: 1
Reputation: 72662
No not the same. If both status
and !checked
evaluate to true, BUT the user doesn't confirm. nothing happens.
However note that it violates the DRY principle when doing it like that.
Upvotes: 5