CODEWITHSUNDEEP
pythondynamicterminalformattingtabular
DBWeinstein
DBWeinstein

Reputation: 9509

How do I dynamically print a table of strings in the terminal?

I need to dynamically create a dict of dicts and then print them in a neat table in the terminal. Eventually, i'm going to be adding to each dict and re-printing the table.

Here's my code so far:

def handy(self, play_deck):
    a = raw_input('How many hands? ')
    for i in range(int(a)):
        h = "hand" + str(i+ 1) # dynamilly create key
        q, play_deck = self.deal(self.full_deck) # pull cards from deck
        self.dict_of_hands.setdefault(h, q) # load up dict of hands

    hand_keys = self.dict_of_hands.keys()
    the_hands = self.dict_of_hands
    print "\n"
    for hand in hand_keys:
        for card in range(len(the_hands[hand].keys())):
            print hand
            print the_hands[hand][card]

and my output is this:

How many hands? 4

hand4
6 of Clubs
hand4
4 of Diamonds
hand1
8 of Diamonds
hand1
10 of Hearts
hand2
10 of Hearts
hand2
5 of Clubs
hand3
9 of Diamonds
hand3
3 of Hearts

I'd like to have:

hand1           hand2           hand3            hand4
2 of hearts     8 of spades     ace of clubs     jack of diomonds
5 of diamonds   ...             ...              ...etc.

The examples i've seen on SO are based on a known number of columns. This needs to be dynamic.

Upvotes: 1

Views: 5638

Answers (3)

DBWeinstein
DBWeinstein

Reputation: 9509

OK. Taking what @ecatmur provided, I now have the following, which seems to work for now.

def handy(self, play_deck):
    a = raw_input('How many hands? ')
    for i in range(int(a)):
        h = "hand" + str(i+ 1) # dynamilly create key
        q, play_deck = self.deal(self.full_deck) # pull cards from deck
        self.dict_of_hands.setdefault(h, q) # load up dict of hands

    hand_keys = self.dict_of_hands.keys()
    the_hands = self.dict_of_hands

    first_cards = []
    second_cards = []
    for hand in the_hands:
        # print the_hands[hand][0]
        first_cards.append(the_hands[hand][0])

    for hand in the_hands:
        # print the_hands[hand][1]
        second_cards.append(the_hands[hand][1])         

    header = self.dict_of_hands.keys()


    table = texttable.Texttable()
    table.header(header)
    table.add_rows([first_cards, second_cards], header=False)
    print table.draw()

and the out put is:

How many hands? 4
+---------------+---------------+------------------+---------------+
|     hand4     |     hand1     |      hand2       |     hand3     |
+===============+===============+==================+===============+
| Jack of Clubs | 9 of Diamonds | Jack of Diamonds | 4 of Spades   |
+---------------+---------------+------------------+---------------+
| 6 of Diamonds | 10 of Spades  | 9 of Diamonds    | Ace of Hearts |
+---------------+---------------+------------------+---------------+

The last piece to the puzzle will be making the following line dynamic:

table.add_rows([first_cards, second_cards], header=False)

Eventually, I'll need each hand to be of varying length.

Upvotes: 1

ecatmur
ecatmur

Reputation: 157414

To convert into a list of rows, use zip:

header = dict_of_hands.keys()
rows = zip(*dict_of_hands.items())

import texttable
table = texttable.Texttable()
table.header(header)
table.add_rows(rows, header=False)
print table.draw()

Upvotes: 1

Oleksii Kachaiev
Oleksii Kachaiev

Reputation: 6232

Look at this recipe: Render tables for text interface

Upvotes: 0

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