Reputation: 3539
I have data like the following:
And what I want is to count the PONo, PartNo, and TrinityID fields with a value in them, and output data like this:
How can I do this counting in SQL?
Upvotes: 4
Views: 11075
Reputation: 58615
select
Job_number, Item_code,
case when RTRIM(PONo) = '' or PONo is null then 0 else 1 end +
case when RTRIM(PartNo) = '' or PartNo is null then 0 else 1 end +
case when RTRIM(TrinityID) = '' or TrinityID is null then 0 else 1 end
as [Count]
from YourTable
Upvotes: 5
Reputation: 74267
Try this:
select Job_Number = t.Job_Number ,
Item_Code = t.Item_Code ,
"Count" = sum( case ltrim(rtrim(coalesce( PONo , '' ))) when '' then 0 else 1 end
+ case ltrim(rtrim(coalesce( PartNo , '' ))) when '' then 0 else 1 end
+ case ltrim(rtrim(coalesce( TrinityID , '' ))) when '' then 0 else 1 end
)
from dbo.my_table t
group by t.Job_Number , t.Item_Code
If you want to exclude data where all the tested fields are null or empty, add a having
clause:
having sum( case ltrim(rtrim(coalesce( PONo , '' ))) when '' then 0 else 1 end
+ case ltrim(rtrim(coalesce( PartNo , '' ))) when '' then 0 else 1 end
+ case ltrim(rtrim(coalesce( TrinityID , '' ))) when '' then 0 else 1 end
) > 0
Easy!
Upvotes: 1