Reputation: 3404
I have a byte array that represents a .jpg file that I want to convert directly to an OpenCV Mat object.
I have something like
byte* data; // Represents a JPG that I don't want to disk and then read.
// What goes here to end up with the following line?
cv::Mat* image_representing_the_data;
Upvotes: 23
Views: 33162
Reputation: 21
Using cv::Mat1b is alot more efficiant and will not copy the memory 2 times more then needed
cv::Mat GetImageFromMemory(uchar* image, int length, int flag)
{
cv::Mat1b data(1, length, image));
return imdecode(data, flag);
}
Upvotes: 2
Reputation: 1567
as @bob mention, this can be done using the Mat constructor.
byte *data;
cv::Mat imageWithData = cv::Mat(sizeOfData, 1, CV_8U, data).clone();
After you have created this matrix, call the reshape function with the number of rows in the image.
cv::Mat reshapedImage = imageWithData.reshape(0, numberOfRows);
Upvotes: 17
Reputation: 31
cv::Mat GetImageFromMemory(uchar* image, int length, int flag)
{
std::vector<uchar> data = std::vector<uchar>(image, image + length);
cv::Mat ImMat = imdecode(data, flag);
return ImMat;
}
the parameter "flag" refers to the type of image, grayscale, color, any depht .. that has opencv defined
Upvotes: 3
Reputation: 39806
the previously mentioned method will work fine, if it's PIXEL data.
if instead, you have a whole jpg FILE in memory, headers, compression, and all, it won't work.
in that case you want:
Mat img = imdecode(data);
which will do the same as imread()
, only from memory, not from a filename
Upvotes: 23