CODEWITHSUNDEEP
c++virtual-functions
K.K
K.K

Reputation: 331

is vptr name mangled in c++?

Even though there are so many articles on how virtual functions are handled in c++, i could not clear one basic doubt. Is vptr variable of derived class overrided by base class variable. Is the ptr varible also name mangled?

Class Base
{
public:
    virtual void test();
};

class Derived 
{
public:
     virtual void test();
};

If I call 

Base b = new Derived();
b->test();

It transforms to 

(*b->vptr[<index>])(b);

Where index points to vtable entry.

My doubt is whether is this vptr also name mangled ?

Upvotes: 1

Views: 604

Answers (2)

c-smile
c-smile

Reputation: 27470

You cannot access vptr in C++ by language means so answer in "no" - no such variable and name and thus no its mangling :)

Upvotes: 1

slartibartfast
slartibartfast

Reputation: 4436

The C++ standard doesn't even acknowledge the existence of a vptr in polymorphic classes because it's an implementation detail and therefore it isn't even a requirement that compilers implement virtual functions in this way. So no, vptr is not a reserved keyword (which is what I think you're trying to ask).

Upvotes: 9

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