CODEWITHSUNDEEP
objective-ccocoa
cutiepie
cutiepie

Reputation: 29

Too many arguments to method call ,expected 1 have 2

I'm calling a JSON URL from the NSURL class. My URL is: 

like://Design_Time_Addresses/IServices/RoleService/json/Role/?name=%@",[textField text]];

When I write "doctor" in the textfield I have to get all the details of doctor through that URL. Similarly when I write "engineer" I have to get all the details of engineer. So it means what I type in the textfield, the name in URL should be replaced with the textfield value. But when I write the code like this:

NSURL *jsonUrl =[NSURL URLWithString:@"http://Design_Time_Addresses/ICloudServices/RoleService/json/Role/?name=%@",[textField text]];
NSString *jsonStr =[[NSString alloc] initWithContentsOfURL:jsonUrl];
NSMutableDictionary *jsonDetails = [[NSMutableDictionary alloc]initWithDictionary:[jsonStr JSONValue]];

As shown here I am using the NSURL class to get this URL.

I am getting an error in the NSURL class. How do I pass the text fields value to a URL?

Upvotes: 0

Views: 2712

Answers (1)

user1071136
user1071136

Reputation: 15725

First line should be 

NSString *urlString = [NSString stringWithFormat:@"http://Design_Time_Addresses/ICloudServices/RoleService/json/Role/?name=%@",[textField text]];
NSURL *jsonUrl =[NSURL URLWithString:urlString];

NSURL URLWithString expects a single string argument, while you are providing two. Since you probably want to construct a single string from the @"http://..." string and [textField text], you should use an NSString method to concatenate them. You can't rely on NSURL to concatenate the string for you.

Upvotes: 3

Related Questions