Giberno
Giberno

Reputation: 1323

php simple html dom parse img html5 attributes?

How to use simple html dom parse img html5 attribute: data-original

$htmls = '<img class="lazy" alt="Nubifragio a Verbania , ferite 2 turiste  Gravi danni, chiesto stato di calamità    foto" title="Nubifragio a Verbania , ferite 2 turiste  Gravi danni, chiesto stato di calamità    foto" data-original="http://www.repubblica.it/images/2012/08/26/130634575-506cc9ae-11b8-4a53-920c-539a3811e46b.jpg" src="http://www.repubblica.it/static/images/homepage/2012/lazy.png" width="130" height="98" style="display: inline; ">';
$html = str_get_html($htmls);
$fata = $html->find('img'); 
foreach($fata as $newimage){
    echo $newimage->data-original; //0
    echo $newimage->src; //http://www.repubblica.it/static/images/homepage/2012/lazy.png
}

I could get the attribute src, but data-original return 0

Upvotes: 13

Views: 15610

Answers (4)

Mike
Mike

Reputation: 552

Using braces would be more efficient:

$newimage->{'data-original'};

Another Example:

<?php
   class foo {
     var $bar = 'I am bar.';
     var $arr = array('I am A.', 'I am B.', 'I am C.');
     var $r   = 'I am r.';
   }

   $foo = new foo();
   $bar = 'bar';
   $baz = array('foo', 'bar', 'baz', 'quux');
   echo $foo->$bar . "\n";
   echo $foo->{$baz[1]} . "\n";

   $start = 'b';
   $end   = 'ar';
   echo $foo->{$start . $end} . "\n";

   $arr = 'arr';
   echo $foo->{$arr[1]} . "\n";

?>

Read more about variables wraped in braces: PHP documentation: Variables

Upvotes: 0

Annapurna Agarwal
Annapurna Agarwal

Reputation: 61

Hope this will work

$thumbs= $video->find('img[class=image]', 0)->{data-original};

Upvotes: 0

Chad
Chad

Reputation: 703

Just an FYI:

I tried:

$newimage['data-original'];

but this is what worked for me:

$property = 'data-original';
$newimage->$property;

Upvotes: 7

Rich Bradshaw
Rich Bradshaw

Reputation: 72975

$newimage->data-original;

means

$newimage->data - original;

A way round this is to try:

$property = 'data-original';
$newimage->$property;

or, to use the alternative syntax:

$newimage['data-original'];

Upvotes: 27

Related Questions