CODEWITHSUNDEEP
phpmysql
PHP Ferrari
PHP Ferrari

Reputation: 15616

Parse HTML tags

I fetches from value from db like:

<p><img alt="" src="images/1.jpg" style="width: 2450px; height: 1054px;" /></p>

and wants to only get src="images/1.jpg" but don't know how. Please guide me

Upvotes: 0

Views: 153

Answers (2)

Sampson
Sampson

Reputation: 268344

If you need the source, use a DOM Parser:

// Construct a new DOMDocument with your fragment
$domDoc = new DOMDocument;
$domDoc->loadHTML( '<p><img src="images/1.jpg" style="width: 2450px;" /></p>' );

// Locate the first image the document
$img = $domDoc->getElementsByTagName( "img" )->item( 0 );

// Echo its src value
echo $img->attributes->getNamedItem( "src" )->nodeValue;

Results: http://codepad.org/oMXGK9Iu

Ideally you would ensure the image elements exist before accessing items #0. Likewise, you would ensure the attributes exist before just leaping out and grabbing them.

Further reading: http://www.php.net/manual/en/class.domdocument.php

If you just want to grab that particular portion of the text, you could use a simple regular expression:

// Prep our html
$html = '<p><img src="images/1.jpg" style="width: 2450px;" /></p>';

// Look for the source string
preg_match( '/src=\".*?\"/', $html, $matches );

// If we found it, spit it out.
echo $matches ? $matches[0] : "No source";

Upvotes: 1

user1317647
user1317647

Reputation:

if alt="" is empty by default and style is width: 2450px; height: 1054px; by default you could use:

<?php
$str = '<p><img alt="" src="images/1.jpg" style="width: 2450px; height: 1054px;" /></p>';
$str = str_replace('<p><img alt="" src="','', $str);
$str = str_replace('" style="width: 2450px; height: 1054px;" /></p>','',$str);
echo $str; //Outputs: images/1.jpg
?>

Upvotes: 0

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