CODEWITHSUNDEEP
javastringnewlineindentation
nain33
nain33

Reputation: 135

newline character indenting? (Java)

I am trying to use \n to create a list of strings but whenever I add more than one string, the string indents up to the point of the previous string so an example output would be:

0 hello nain
            1 test nain
                       2 huh nain

I don't know why its doing this. Here's the code where I create the string:

            String[] posts = currentTopic.getMessages("main");
            //String[] postsOutput = new String[posts.length];
            String postsOutput = "0 " + posts[0];

            for(int i = 1; i < posts.length; i++){
                postsOutput += "\n" + i + " " + posts[i];
                //postsOutput[i] = i + posts[i];
            }

            sc.close();
            return postsOutput;

I also tried moving the \n to the end of the appending but the result is still the same. Any help would be appreciated.

Thanks

Upvotes: 2

Views: 10233

Answers (4)

halex
halex

Reputation: 16403

I think this is a good example to use String.format because %n always uses the system specific line seperator. Inside your loop write:

postsOutput += String.format("%n%d %d", i, posts[i]);

Upvotes: 2

Alex
Alex

Reputation: 25613

You should use the property System.getProperty("line.separator"), that holds the underlying system newline character.

String newline = System.getProperty("line.separator");
String[] posts = currentTopic.getMessages("main");
//String[] postsOutput = new String[posts.length];
String postsOutput = "0 " + posts[0];

for(int i = 1; i < posts.length; i++){
    postsOutput += newline  + i + " " + posts[i];
    //postsOutput[i] = i + posts[i];
}

sc.close();
return postsOutput;

Upvotes: 1

Endy
Endy

Reputation: 696

Try \r\n, i.e. carriage return and newline.

Upvotes: 3

PypeBros
PypeBros

Reputation: 2646

that looks like you're on a system where "\n" just gets down (line feed) and you're missing the required carriage return.

That shouldn't be something you should care yourself: line.separator property is adjusting to the host operating system so that it behaves like System.out.println.

Upvotes: 6

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