CODEWITHSUNDEEP
c#regex
user1260827
user1260827

Reputation: 1520

split string by char C#

I have a string that contain the following text:
[l=9;f=0;r=5;p=2]
There may be more than one:
[l=9;f=0;r=5;p=2];[l=9;f=0;r=6;p=2]

I want to get the array of strings(for second example):

[l=9;f=0;r=5;p=2]
[l=9;f=0;r=6;p=2]

I tried this but it split not correctly:

Regex.Split(seat, "(?=])");

PS. regexp not mandatory.

Upvotes: 1

Views: 238

Answers (6)

Mark Reed
Mark Reed

Reputation: 95242

In your code:

Regex.Split(seat, "(?=])");

Seems like you're just missing the actual semicolon, and a backslash for the brakcet, from your regex. This works:

 string[] data = Regex.Split(seat, ";(?=\\[)");

Upvotes: 0

Enigmativity
Enigmativity

Reputation: 117029

Here's a LINQ approach:

Func<string, string> process = s =>
    String.Format("[{0}]",
        String.Join("];[",
            s
                .Split('[')
                .Select(x => x.Split(']'))
                .SelectMany(x => x)
                .Where(x => x != "" && x !=";")));

At the very least it works. :-)

Use it like this:

var result = process("[l=9;f=0;r=5;p=2];[l=9;f=0;r=6;p=2]");

Upvotes: 0

Arif Eqbal
Arif Eqbal

Reputation: 3138

The below pattern might help you use the Split option of Regex

string input = "[l=9;f=0;r=5;p=2];[l=9;f=0;r=6;p=2]";
string pattern = @"(?<=\]);";
Regex regex = new Regex(pattern);
string[] data = regex.Split(input);

Upvotes: 3

Huusom
Huusom

Reputation: 5912

Why don't you use regex capturing?

The pattern \[l=(\d);f=(\d);r=(\d);p=(\d)\] will capture the values in each array.

Example:

private static IEnumerable<dynamic> Match(string text)
{
    return Regex.Matches(text, @"\[l=(\d);f=(\d);r=(\d);p=(\d)\]")
        .Cast<Match>()
        .Where(m => m.Success)
        .Select(m => new { l = m.Groups[1].Value, f = m.Groups[2].Value, r = m.Groups[3].Value, p = m.Groups[4].Value });
}

static void Main(string[] args)
{
    foreach (var result in Match("[l=9;f=0;r=5;p=2];[l=9;f=0;r=6;p=2]"))
        Console.Out.WriteLine("Setting: {0}, {1}, {2}, {3}", result.l, result.f, result.r, result.p);

    foreach (var result in Match("[l=9;f=0;r=5;p=2]"))
        Console.Out.WriteLine("Setting: {0}, {1}, {2}, {3}", result.l, result.f, result.r, result.p);
}

Upvotes: 0

L.B
L.B

Reputation: 116108

string input = "[l=9;f=0;r=5;p=2];[l=9;f=0;r=6;p=2]";
var list = Regex.Matches(input, @"\[.+?\]")
            .Cast<Match>()
            .Select(m => m.Value)
            .ToList();

Upvotes: 8

g45rg34d
g45rg34d

Reputation: 9660

"[l=9;f=0;r=5;p=2];[l=9;f=0;r=6;p=2]".Split(new string[] { "];" }, StringSplitOptions.None)

And then append "]" back to each item in the array...

Ugly but should work.

Upvotes: 0

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