CODEWITHSUNDEEP
pythonarraysrandom
gdlm
gdlm

Reputation: 353

Big array with random numbers with python

I need to generate a big array (or list) with random numbers ( 10⁵ numbers) . I was trying like that:

vet = random.sample(range(10),100000)

But when I try to run :

vet = random.sample(range(10),10000)

File "/usr/lib/python2.7/random.py", line 320, in sample raise ValueError("sample larger than population") ValueError: sample larger than population

Any solution?

tkns

Upvotes: 12

Views: 66047

Answers (3)

marchelbling
marchelbling

Reputation: 1939

What you want is

[random.random() for _ in xrange(100000)]

From the random module documentation:

random.sample(population, k) Return a k length list of unique elements chosen from the population sequence. Used for random sampling without replacement.

so when calling random.sample(range(10), 100000) you're trying to extract 100000 unique elements in a sequence of length 10 which obviously can't work.

Note that

  • random.random() returns a floating value between [0 ; 1)
  • random.randrange([start], stop[, step]) returns a random element from the sequence range([start], stop[, step])
  • random.randint(a, b) returns an integer value in [a ; b]
  • when using random.sample, the equality len(population) >= k must hold

Upvotes: 32

Emanuel Fontelles
Emanuel Fontelles

Reputation: 906

You can you the numpy function and create an array with N space filled with a random number

import numpy as np

vector_size = 10000

one_dimensional_array  = np.random.rand(vector_size)
two_dimensional_array  = np.random.rand(vector_size, 2)
tree_dimensional_array = np.random.rand(vector_size, 3)
#and so on

numpy.random.rand

You can create matrix of random numbers using the function below and arrays also.

Upvotes: 3

g.d.d.c
g.d.d.c

Reputation: 47988

I think you're after something like this:

vet = [random.randint(1,10) for _ in range(100000)]

Upvotes: 13

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