CODEWITHSUNDEEP
sql-server-2008
user1423997
user1423997

Reputation: 111

SQL Top 10 Totals

How do I select the top 10 descending totals from a column (Amount) based on another column (ID)?

This is what I'd like my desired results to look like:

(Top 1)
Row 1: ID: 9, Amount: 10, Total: 15
Row 2: ID: 9, Amount: 5, Total: 15

(Top 2)
Row 3: ID: 500, Amount: 14, Total: 14

(Top 3)
Row 4: ID: 27, Amount: 3, Total: 9
Row 5: ID: 27, Amount: 3, Total: 9
Row 6: ID: 27, Amount: 3, Total: 9 etc.

Thanks.

Upvotes: 0

Views: 167

Answers (3)

valex
valex

Reputation: 24144

select * from t where id in 
(select top 10 id from t group by id order by sum(Amount) desc)

if you need the final results to be ordered by sum(Amount) here is a query:

select t.*,t2.sum_amount from t 
inner join (select top 10 id,sum(Amount) as sum_amount 
                 from t 
              group by id 
              order by sum(Amount) desc) t2
        on (t.Id = t2.id)
order by t2.Sum_amount desc ,id

Upvotes: 0

Joe G Joseph
Joe G Joseph

Reputation: 24116

try this:

;with cte as
    (select *,
     row_number() over(partition by ID order by Amount desc) as row_num
     from  your_table),
 cte1 as(
    select ID,SUM( Amount) as Total
    from   your_table
    group  by ID)
select top 10 c.ID,C.Amount,c1.Total
from cte c join cte1 c1
on c.ID=c1.ID
order by C1.Total desc


SQL Fiddle Demo

Upvotes: 1

oryol
oryol

Reputation: 5248

select Row, ID, Amount, Total from ( select Row, ID, Amount, Total ,rank() over (order by Total desc) as Rank from t1 ) rt where Rank between 1 and 10

Upvotes: 0

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